1. Y=360-54=306 (sum of angles at a point) W=54o(base a

answer questions

1. Y=360-54=306 (sum of angles at a point)
W=54o(base angles of isosceles)
X=180-(2*54)=72o
Z=54/2=27o(base angles of isosceles)
2.
a. X=38o
Y=180-(85+38)=57o
b. X=50o
From the triangle, the included angle=180-(45+50)=85o
85+y+x=180
Y=180-(85+50)=45o
3.
a. The figure is made of a trapezium and a square
Area of trapezium =1/2h(a+b)
½(3)(8+4)=18
Area of square=L*L=5*5=25
Total area=43m2

4. x=hypotenuse in all the cases
Hp= √ h2 +b2=¿
a. x= √62 +82=10 cm
b. x= √62 +72=9.2 cm
c. x= √262 + 412=48.5 cm
d. x= √ 202 +992 =101cm
5. The height of the coconut is the hypotenuse
Hp= √h2 +b2
Hp= √72 +52=8.6 m
6.
a. x=hypotenuse
Hp= √ h2 +b2=¿
Base of the right angle triangle=9-4=5m
i. x= √62 +82=10 cm
b) height of the right angle triangle=15-9=6m
x=base
b= √ Hp2 −b2
x= √232−62=22.2 m

7.
Angle size
a 130o
b 50o
C 88o
d 42o
e 97o
f 33o
g 147o
h 123o
i 57o
j 33o
k 140o
l 33o
m 40o

8.
Angle size
a 132o
b 48o
C 39o
d 74o
f 74o
g 48o
h 58o
k 74o
m 106o

n 39o
p 113o
q 67o
r 53o
s 127o
t 58o
9.
Unknown side =6*1.5 or 3*3=9
For the second set,
Linear 6/3=8/4=4/2=2
unknown side =2*8=16

10.
a.
x=height
b= √ Hp2 −h2
b= √52−42=3
x=base
b= √ Hp2 −b2
√42−22=3.5
b.