CHEM 110 Assignment: Comprehensive Chemistry Review for Beginners

This Chemistry 110 assignment solution provides detailed answers to a range of chemistry problems. The assignment covers topics including balancing chemical equations, identifying acid-base reactions, understanding ionic bond formation, and determining molar mass. It also includes questions on Lewis structures, naming chemical compounds, calculating the mass of elements, identifying reaction types, and determining molecular formulas using percentage composition and molar mass. Furthermore, the solution provides step-by-step calculations for determining the yield of a chemical reaction. The assignment covers a comprehensive review of fundamental chemistry concepts, making it a valuable resource for students studying introductory chemistry. The solution includes formulas, and explanations for each question, offering a complete guide to the assignment.

CHEMISTRY 110
Assignment
[DATE]

Question 1
Balanced chemical equation
Sum of coefficients = 1 + 8 + 5 + 6 = 20
Question 2
Here, an acid is reacting with the base and thus, this reaction is an acid-base reaction.
Question 3
In order to form a stable ion, magnesium atom losses two electrons and forms Mg+2.
Question 4
The molecule of has two equivalent Lewis structure or resonance structure as shown
below.
Question 5
Name of compound = Aluminium sulfate
1

Formula of compound
Here,
Molar mass of Al = 27
Molar mass of S = 32.1
Molar mass of O = 16
Hence,
Molar mass of Aluminium sulfate = 2 (27) + 3 {32.1 + (16*4)} = 342.3 gram per mole
Question 6
3.75 moles of Cl represent = n grams of Cl
Mass of Cl = 35.5 gram per mole
1 mole has 35.5 gram of Cl
And thus, 3.75 moles would have n = 35.5*3.75 = 133.125 gram of Cl
Question 7
Mass of O = 16
Mass of N = 14
Mass of H = 1
Total mass of 1 mole of
Mass of O in compound = 16*3 = 48
2

Question 8
atoms of Ca have 40 grams of Ca
1 atom of Ca would have =
Question 9
Reaction
Here, Zn replace the hydrogen from chlorine to form ZnCl2. Hence, it would be a single
displacement reaction.
Question 10
Answer: 24.03050 which is atomic weight of Mg.
Question 11
Name of compound = Calcium phosphate
Formula of compound
Question 12
Formula of compound
Name of compound = Dinitrogen pentoxide
3

Question 13
Bond angle around a central in ammonia = 107o
Question 14
A chemical equation is said to be balanced when the number of atoms presents in the
reactants (left side of equation) is exactly the same as the number of atoms of produced (right
side of equation).
Example
Unbalanced equation
Atoms of reactant side = 2
Atoms of product side = 3
Balanced equation
Atoms of reactant side = 3
Atoms of product side = 3
Question 15
Ionic bond – This type of bond forms when one atom donates an electron to another electron
to make it more stable, then the bond is termed as ionic bond. The atom which discharges
electron becomes positively charged ion. and the atom which receives the electron becomes
negatively charged ion.
4

Sodium atom donates one electron to chlorine atom which means they have formed an ionic
bond an as a result of these two ions are formed i.e. Na+ and Cl-.
Question 16
Electron dot-structure of
Question 17
Type of bond in HBr = Covalent
Question 18
Geometry around a central atom in
5

Question 19
Name of compound = Magnesium Fluoride
Formula of compound
Question 20
Carbon % in unknown compound = 40%
Hydrogen % in unknown compound = 6.67%
Oxygen % in unknown compound = 53.33%
Molar mass of compound = 150 gram per mole
Molecular formula =?
In 100 gram of the compound there would be
Empirical formula =
Further,
Now,
Molecular formula =
6

Question 21
Yield of water =?
Water in product = 5 gram
Oxygen amount = 150 gram
Molar mass of oxygen = 32 gram per mol
Mol of oxygen = Mass/Molar mass = 150/32 = 4.688 moles
Balanced equation
Mole of water formed through reaction = (2/1) *4.688 = 9.375 moles
Molar mass of water = (2*1.008) + (1*16) = 18.016 g/mol
Mass of water = Number of mols of water * Molar mass = 9.375 * 18.02 = 1.689*10^2 gram
% yield = (Actual mass/ Theoretical mass) *100 = (5/1.689*10^2) *100 = 2.96%
Yield of water would be 2.96%.
Question 22
Formula of compound
Name of compound = Iron trichloride OR Iron (III) chloride
Question 23
(D) Barium sulfate
7

Question 24
Name of compound = Chromium (III) bromide
Formula of compound
Question 25
Formula of compound
Name of compound = Sodium Nitrate
8