Algebra - Solved Problems and Answers

Running head: ALGEBRA
ALGEBRA
Name of the student:
Name of the University:
Author’s note:

1ALGEBRA
Answers:
Saturday:
1. FC = 27% = 0.27 and MC = 1.85 in/ft. Therefore, SMD = FC – MC = 0.27 – 1.85 =
-1.58 in/ft.
2. AA = 1.5” and SMD = 0.99 in/ft. Therefore, Depth = AA/SMD = 1.51515 in/ft.
3. Given PWP = 12%, PAW = 8.8”, RZ = 48” and MAD = 20%.
Therefore, MC = PWP + (PAW/ RZ) – [(PAW/RZ)*MAD] = 0.12 + (8.8/48) – [(8.8/48)*0.20] =
0.267 in/ft.
4. Depth = 2.2’ = 26.4”, MAD = 15% = 0.15, FC = 3.2 in/ft and PWP = 13% = 0.13. Therefore,
AA = Depth * SMD = Depth * (FC - PWP) * MAD = 26.4 * (3.2 – 0.13) * 0.15 =
26.4*3.07*0.15 = 12.15”
5. AW = 18% = 0.18, PWP = 0.99in/ft, MAD = 15% = 0.15. Therefore, MC = FC – SMD = (AW
+ PWP) – (AW*MAD) = (0.18 + 0.99) – (0.18*0.15) = 1.17 – 0.027 = 1.143 in/ft
6. MC = 1.23 in/ft, MAD = 22% = 0.22 and SMD = 0.24 in/ft. Therefore, PWP = FC – AW =
(SMD + MC) – (SMD/MAD) = (0.24 + 1.23) – (0.24/0.22) = 1.47 – 1.09 = 0.38in/ft.
7. AW = 21% = 0.21 and PAW = 12”. Therefore, RZ = PAW/AW = 12/0.21 = 57.14”.
8. AA = 3”, MC = 2.3 in/ft, AW = 25% = 0.25in/ft, PWP 84 in/ft, FC = 3.84 in/ft and SMD =
1.54 in/ft. Therefore, Depth = AA/SMD = AA/ (FC - MC) = 3/1.54 = 1.95 in/ft.

2ALGEBRA
Tuesday:
1. MC = 2in/ft, PWP = 12% = 0.12 , AW = 2.76 in/ft and AA = 3”. Therefore, depth =
AA/SMD = AA/(FC - MC) = AA/(AW + PWP) –MC = 3/0.88 = 3.40”
2. Given, PAW = 12”, MAD = 50%= 0.50 and SMD = 1.5 in/ft. Therefore, RZ = PAW/AW
= (PAW*MAD)/SMD = (12*0.50)/1.5 = 4.
3. MC = 2 in/ft, PWP = 15% = 0.15 and AW = 2.2 in/ft. Therefore, SMD = FC – MC =
AW = PWP – MC = 2.2 + 0.15 - 2 = 0.35.
4. RZ = 62”, AW = 31% = 0.31, SMD = 74 in/ft, PWP = 0.67 in/ft, MAD = 20% = 0.20 and
PAW = 11”. Therefore, FC = AW + PWP = 0.31 + 11 = 11.31 = 0.11%.
5. AA = 3.5’ = 42”, SMD = 1.3 in/ft. Therefore, Depth = AA/SMD = 42/1.3 = 32.30”
6. CL = 4, L = 1.65, SL = 1.25 and RZ = 48”. Therefore, PAW = CL + L + SL = 4 + 1.65 +
1.25 = 6.9”.

3ALGEBRA
Wednesday
1. Clay loam soil saturation = 40% = 0.40, FC = 28% = 0.28, PWP = 16% = 0.16, Air Dry =
13% = 0.13 and MC = 23% = 0.23. Therefore, SMD = FC – MC = 0.28 – 0.23 = 0.05.
2. RZ = 4’, AW = 1.25 in/ft, ETC = 0.25 in/day and MAD = 60%. Therefore, PAW = AW *
RZ = 48 * 1.25 = 60”.
3. SMD = 2.33 in/ft and RZ = 36” and AA = 4”. Therefore, Depth = AA/SMD = 4/2.33 =
1.71”.
4. Given RZ = 38” , AW = 1.25 in/ft, ETC 0.25 in/ft and MAD = 60% = 0.60. Therefore,
PAW = AW * RZ = 1.25*38 + 47.5 in/ft.
5. PWP = 1.8 in/ft and AW = 1.6 in/ft. Therefore, FC = PWP +AW = 1.8 + 1.6 = 3.4 in/ft.
6. Given AA = 43”, CL =3.375, L =2.775, SL = 2.5. Therefore, PAW = CL + L + SL =
3.375 + 2.775 + 2.5 = 8.65”