1APPLIED MANAGEMENT STATISTICS Table of Contents Answer to the question 1............................................................................................................2 Part (a)....................................................................................................................................2 Part (b)....................................................................................................................................2 Answer to the question 2............................................................................................................2 Part (a)....................................................................................................................................2 Part (b)....................................................................................................................................2 Part (c)....................................................................................................................................3 Part (d)....................................................................................................................................3 Answer to the question 3............................................................................................................4 Part (a)....................................................................................................................................4 Part (b)....................................................................................................................................4 Answer to the question 4............................................................................................................5 Part (a)....................................................................................................................................5 Part (b)....................................................................................................................................5 Part (c)....................................................................................................................................5 Part (d)....................................................................................................................................6 Answer to the question 5............................................................................................................6 Bibliography...............................................................................................................................8
2APPLIED MANAGEMENT STATISTICS Answer to the question 1 Part (a) College student is the population. Part (b) To analyse this study on transportation system in Barcelona different department student has been taken as a sample. Every department has been taken as a strata and by using simple random sampling lottery method a limited percentage of students are taken in the sample. Answer to the question 2 Part (a) The number of observations (n) = 25 Mean = 4 Standard deviation = 1.2 The 95% confidence interval for the mean delivery time is Mean±1.96 * (standard deviation / sqrt (n)) = 4±1.96 *(1.2/ sqrt (25)) = (3.53, 4.47) 3.53≤meandeliverytime≤4.47 Part (b) Null hypothesis: The delivery time of the product does not exceed 3 days. Alternative hypothesis: The delivery time of the product is exceed 3 days.
3APPLIED MANAGEMENT STATISTICS T-test output Part (c) The 95% confidence interval is 3.53≤meandeliverytime≤4.47 According to manager the delivery time does not exceed 3 days. But in the 95% confidence it has been seen that the average delivery time is lies between 3.53 and 4.47 which is larger than the 3 days. So the claim of the manager is not true. Thus claim of the manager is rejected. Part (d) Test statistic = 4.17 P-value= 0.0002
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4APPLIED MANAGEMENT STATISTICS Alpha = 0.05 It is clear that the P-value < alpha (alpha=0.05). Hence the null hypothesis is significant. Thus it may be summarized that the delivery time of the product is exceed 3 days. Answer to the question 3 Part (a) The number of kids (n) = 100 The mean of the study = 25 Standard deviation = 5 The 99% confidence interval of the mean of kinds is Mean±2.58 * (standard deviation / sqrt (n)) = 25±2.58 *(5/ sqrt (100)) = 25±2.58 * 0.5 = (23.71, 26.29) 23.71≤meanofkinds∈Barcelonaatage(6−11)≤26.29 Part (b) It has been seen that the mean of all kids which age 6-11, at 99% confidence interval is 23.71 and 26.29. The mean watching time is 25. Hence the 99% confidence lies within the mean time. So the 99% confidence interval is accepted.
5APPLIED MANAGEMENT STATISTICS Answer to the question 4 Part (a) In the study the independent variable is work experience and the dependent variable is annual income. From the regression table it has been seen that the correlation between these two variable is 0.93. Thus this indicates that the relationship between the annual income and work experiences is positive and strong. Part (b) The R-square of the analysis is 0.86. Thus this means that the relationship between the annual income and work experiences is 86% strong and positive. Part (c) The regression model is as below Annual income = 17351+1362 * work experiences The slope of the regression model is 17351 and the coefficient of the independent variable that is work experiences is 1362.
6APPLIED MANAGEMENT STATISTICS Part (d) Given that Work experience = 15 years Thus Annual income = 17351+1362 * work experiences = 17351+ (1362 * 15) = 37781 Hence the average annual income of a person at 15 years experiences is 37781. Answer to the question 5 The total number of observation is 293. Hence the mean will need to generate 3 digit numbers. The first sample observations on the list would like 001 and the last would be 293. Let us start to take some samples with 3 digit number and start with first row from the table. The samples are as below 492, 808, 892,435, 779, 002, 838, 116, 307, 275, 898,630, 234,861, 870, 416, 570, 746, 808, 612,980, 839,734, 920,775, 450,914, 389, 865, 923, 250, 788, 612, 978, 496, 976, 539, 155, 008, 078, 629, 939, 123, 0.45, 484, 598, 560,952, 066, 412. Now from the following numbers which is larger than 293 is rejected. Moreover which is repeated then a single one from the repetition number has been taken. Hence the required 10 sample observations are as below 002,116, 275, 234, 250, 155,008, 078, 123, 045.
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7APPLIED MANAGEMENT STATISTICS Therefore the selected mobile phones are iPhone 7 plus, LG G4, Sony Xperia XA1 ultra, HTC Desire 300, HTC Desire C, LG G3 Beat, Apple iPhone 8, Samsung Galaxy Note 2, LG Nexus 5X, Samsung Galaxy S7.
8APPLIED MANAGEMENT STATISTICS Bibliography De Winter, J.C., 2013. Using the Student's t-test with extremely small sample sizes.Practical Assessment, Research, and Evaluation,18(1), p.10. Giometto, A., Formentin, M., Rinaldo, A., Cohen, J.E. and Maritan, A., 2015. Sample and population exponents of generalized Taylor’s law.Proceedings of the National Academy of Sciences,112(25), pp.7755-7760. Kruschke, J.K., 2013. Bayesian estimation supersedes the t test.Journal of Experimental Psychology: General,142(2), p.573. Lee, D.K., 2016. Alternatives to P value: confidence interval and effect size.Korean journal of anesthesiology,69(6), p.555. Morey, R.D., Hoekstra, R., Rouder, J.N., Lee, M.D. and Wagenmakers, E.J., 2016. The fallacy of placing confidence in confidence intervals.Psychonomic bulletin & review,23(1), pp.103-123. Pataky, T.C., Vanrenterghem, J. and Robinson, M.A., 2015. Zero-vs. one-dimensional, parametric vs. non-parametric, and confidence interval vs. hypothesis testing procedures in one-dimensional biomechanical trajectory analysis.Journal of biomechanics,48(7), pp.1277- 1285. Pencina,M.J.,Navar-Boggan,A.M.,D'AgostinoSr,R.B.,Williams,K.,Neely,B., Sniderman, A.D. and Peterson, E.D., 2014. Application of new cholesterol guidelines to a population-based sample.N Engl J Med,370, pp.1422-1431. Reyad, O. and Kotulski, Z., 2015, November. Image encryption using koblitz’s encoding and new mapping method based on elliptic curve random number generator. InInternational
9APPLIED MANAGEMENT STATISTICS Conference on Multimedia Communications, Services and Security(pp. 34-45). Springer, Cham. Sivakumar, T. and Venkatesan, R., 2016. A New Image Encryption Method Based on Knight's Travel Path and True Random Number.J. Inf. Sci. Eng.,32(1), pp.133-152.