This document provides study material and solved assignments on Applied Quantitative Method. It includes topics like frequency distribution, histograms, mean, median, mode, correlation coefficient, regression equation, and coefficient of determination.
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Running head: APPLIED QUANTITATIVE METHOD Applied Quantitative Method Name of the Student Name of the University Course ID
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2APPLIED QUANTITATIVE METHOD Question 1 Question a Table 1: Frequency distribution for City Restaurant Meal Costs City Restaurant Meal Costs Class Frequenc y Mid- point Relative Frequency Cumulative frequency (less than) Cumulative frequency (more than) Cumulative relative frequency (less than) Cumulativ e relative frequency (more than) 26-33729.50.1475014100 33-40336.50.0610432086 40-471043.50.220404080 47-541050.50.230306060 54-61757.50.1437207440 61-68564.50.142138426 68-75271.50.044488816 75-82278.50.044669212 82-89285.50.04484968 89-96292.50.045021004 Total501 Table 2: Frequency distribution for Suburban Restaurant Meal Costs Suburban Restaurant Meal Costs Class Frequenc y Mid- point Relative Frequency Cumulative frequency(les s than) Cumulative frequency (more than) Cumulative relative frequency (less than) Cumulative relative frequency (more than) 26-33629.50.1265012100 33-40636.50.1212442488 40-471343.50.2625385076 47-541450.50.2839257850 54-61557.50.144118822 61-68264.50.044669212 68-75171.50.02474948 75-82278.50.04493986 82-89085.50491982 89-96192.50.025011002 Total501
3APPLIED QUANTITATIVE METHOD Question b 26-3333-4040-4747-5454-6161-6868-7575-8282-8989-96 0 2 4 6 8 10 12 Histogram for City Restaurant Meal Costs Class Frequency Figure 1: Histogram of City Restaurant Meal Costs 26-3333-4040-4747-5454-6161-6868-7575-8282-8989-96 0 2 4 6 8 10 12 14 16 Histogram for Suburban Restaurant Meal Costs Class Frequency Figure 2: Histogram of Suburban Restaurant Meal Costs
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4APPLIED QUANTITATIVE METHOD Question c Table 3: Mean, Median and Mode for City Restaurant City Restaurant Meal Costs Mean52.4 Median52 Mode53 Table 4: Mean, Median and Mode for Suburban Restaurant Suburban Restaurant Meal Costs Mean48.04 Median47.5 Mode48 Question 2 Question a The above data represents a sample. In statistical and quantitative research sample refers to the part of the data collected from a large population. In the above scenario, the supermarket deals with many products all having different marketing strategies and a different advertising expenditure. Of the many products, only 12 products are selected for analysis purpose and therefore, it is a sample. Population implies all elements having common characteristics comprising the entire universe (Fisz and Bartoszyński 2018). Sample on the other hand represents a subgroup of the members of population.
5APPLIED QUANTITATIVE METHOD Question b Standard deviation of annual sales Standarddeviation=√1 N∑ i=1 12 (Xi−X)2 ¿√∑Xi 2 N−(X)2 ¿√494600 12−(201.67)2 ¿√41216.67−40669.44 ¿√547.22 ¿23.39 Question c InterquartileRange=ThirdQuartile(Q3)−FirstQuartile(Q1) ¿82.5−50 ¿32.5 The measure of Interquartile range is preferred over standard deviation in situation where the distribution has high degree of skewness or has several outliers. As IQR is relatively less sensitive to skewness or presence of outlier compared to standard deviation, use of IQR is more effective than the use of standard deviation (Rees 2018). For the above data, in the series of annual expenditures, there are some extreme values that can be considered as outliers and therefore, IQR is preferred to standard deviation in this case. Question d
6APPLIED QUANTITATIVE METHOD Table 5: Correlation Coefficient between Annual Sales and Advertising Expenditure Annual Sales ($1000) Annual Advertising Expenditure ($1000) Annual Sales ($1000)1 Annual Advertising Expenditure ($1000)0.801 The obtained correlation coefficient between annual sales and annual advertising expenditure is 0.80. Positive value of correlation coefficient suggests that there is a positive association between annual sales and advertising expenditure. That is with increase in advertising expenditure, annual sales of the supermarket are likely to increase and vice versa. The estimated correlation coefficient has a value closer to 1 meaning that there is a strong positive association between annual sales and advertising expenditure. Question 3 Question a The variable that influence value of other variable is considered as dependent variable. Advertising expenditure is an important part of marketing strategy that likely to influence annual sales of a company. Advertising expenditure helps in boosting annual sales by promoting the product. As annual sales is likely to depend on advertising expenditure, it is considered as dependentvariableand advertising expenditureistaken asindependent variable. Question b The regression equation to be estimated is given as y=a+bx y: Dependent variable: Annual sales
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7APPLIED QUANTITATIVE METHOD x: Independent variable: Advertising expenditure a: Intercept b: Slope coefficient The formula to estimate intercept and slope coefficient of a regression equation is given as Slope(b)=∑(xi−x)(yi−y) ∑(xi−x)2 Intercept(a)=y−ax Table 6: Computation of slope and regression coefficient of regression Productyxxi - Mean xyi - Mean y(xi-Mean x) (yi-Mean y)(xi - Mean x)^2 1200809.17-1.67-15.2884.03 2200809.17-1.67-15.2884.03 324012049.1738.331884.722417.36 418050-20.83-21.67451.39434.03 517040-30.83-31.67976.39950.69 616040-30.83-41.671284.72950.69 721050-20.838.33-173.61434.03 82309019.1728.33543.06367.36 923011039.1728.331109.721534.03 1020060-10.83-1.6718.06117.36 1121050-20.838.33-173.61434.03 12190809.17-11.67-106.9484.03 Total24208505783.337891.67 Slope(b)=∑(xi−x)(yi−y) ∑(xi−x)2 ¿5783.33 7891.67 ¿0.7328 Intercept(a)=y−bx
8APPLIED QUANTITATIVE METHOD ¿201.6667−(0.7328×70.83) ¿149.7571 Using the estimated intercept and slope, the regression equation is obtained as y=149.7571+0.7328x Intercept of the regression equation is 149.7571. This shows that the supermarket records an annual sales of $149.7571 thousand dollar when advertising expenditure is zero. Theregressioncoefficientforadvertisingexpenditure0.7328.Thepositiveregression coefficient suggests that advertising expenditure has a positive impact on annual sales of supermarket(Chatterjeeand Hadi 2015). More preciously, for 10 percent increase in advertising expenditure, annual sales increases by 7.3 percent. Question c Table 7: Calculation of coefficient of determination Productyxxi-Mean x yi-Mean y (xi-Meanx) (yi-Meany) (xi-Mean x)^2(Yi-MeanY)^2 1200809.17-1.67-15.2884.032.78 2200809.17-1.67-15.2884.032.78 324012049.1738.331884.722417.361469.44 418050-20.83-21.67451.39434.03469.44 517040-30.83-31.67976.39950.691002.78 616040-30.83-41.671284.72950.691736.11 721050-20.838.33-173.61434.0369.44 82309019.1728.33543.06367.36802.78 923011039.1728.331109.721534.03802.78 1020060-10.83-1.6718.06117.362.78 1121050-20.838.33-173.61434.0369.44 12190809.17-11.67-106.9484.03136.11 Total24208505783.337891.676566.67
9APPLIED QUANTITATIVE METHOD CorrelationCoefficient(r)=∑(xi−x)(yi−y) √∑(xi−x)2 ∑(yi−y)2 ¿5783.33 √7891.67×6566.67 ¿5783.33 √51821944.44 ¿5783.33 7198.746 ¿0.8034 Coefficientofdetermination=r2 ¿(0.8034)2 ¿0.6454 The obtainedvalue of coefficientof determinationis0.6454. The measureof coefficient of variation suggests proportion of variation in dependent variable as accounted by the independent variable. From the computed value of coefficient of determination, it can therefore be said that advertising expenditure accounts for almost 65 percent variation in annual sales of the supermarket. Question 4 Scientific training Grassroots trainingTotal Recruited from Holmes Students 2882110 External Recruitment452267 Total73104177
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10APPLIED QUANTITATIVE METHOD Question a Probability that a randomly chosen player will be from Holmes OR receiving Grassroots training is obtained as P(Holmes∪Grassrootstraining)=P(Holmes)+P(Grassrootstraining)−P(Holmes∩Grassrootstraining) ¿110 177+104 177−82 177 ¿110+104−82 177 ¿132 177 ¿0.75 Question b Probability that a randomly selected player will be External AND be in scientific training can be obtained as P(External∩Scientifictraining)=45 177 ¿0.25 Question c Given that a player is from Holmes, the probability that he is in scientific training can be obtained as P(Scientfictraining/(Holmes))=P(Scientifictraining∩Holmes) P(Holmes) ¿28 110
11APPLIED QUANTITATIVE METHOD ¿0.25 Question d Two events are independent when products of marginal probability are same as the probability of joint occurrence of the events. Table 7: Probability table of recruitment and training Scientific training Grassroots trainingTotal Recruited from Holmes Students 0.160.460.62 External Recruitment 0.250.120.38 Total0.410.591
12APPLIED QUANTITATIVE METHOD Table 8: Marginal probability of training and recruitment Scienti fic trainin g Grassroo ts training Tota l Recruited from Holmes Students 0.260.370.62 External Recruitme nt 0.160.220.38 Total0.410.591 The table above shows products of marginal probabilities of two events do not match with probability of joint occurrence indicating that training is independent from recruitment. This in turn suggests that selection of students either from Holmes or from external teams do not depend on the level of training that the students have. Question 5 Question a Average price of Surfers Paradise apartment is given as = $0.9 million Standard deviation of prices is given as = $270,000 = $270,000/1000000 = $0.27 million Mean(μ)=0.9 Standarddeviation(σ)=0.27 Probability that apartment will sell for over $1.5 million is obtained as P[X>1.5]=P[X>1.5−0.9 0.27] ¿P[Z>2.2222]
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13APPLIED QUANTITATIVE METHOD ¿1−P[Z≤2.2222] ¿1−0.9868 ¿0.0132 Question b Probability that apartment will sell for over $0.8 million but less than $0.9 million P[0.8<X<0.9]=P[0.8−0.9 0.27<X<0.9−0.9 0.27] ¿P[−0.37<Z<0] ¿P[Z<0]−P[Z←0.37] ¿0.5−{1−P[Z<0.37]} ¿0.5−{1−0.6443} ¿0.5−0.3557 ¿0.1443 Question 6 Question a Z distribution does not make any assumption about the type of distribution. The only assumption needed for application of Z distribution is that the distribution has a mean and a standard deviation.For differentdistributionfamilies,there isadifferentmethodfor computing Z scores. Z distribution though can be used for any form of distribution however the extremity of Z score is weaker for distribution other than normal (Cox 2018). Therefore,
14APPLIED QUANTITATIVE METHOD despite the fact that the distribution of apartment is not normal, Z distribution can still be used to test assistant’s research findings. Question b Given the sample size (n) = 45 It is found that 11 out of 45 investors agree to invest more than $1 million. Therefore, the obtained sample proportion is ^P=11 45 ¿0.24 30% of the investors need to invest more than $1 million make the fund profitable. Therefore, the desires proportion is P0=30 100 ¿0.30 Using the central limit theorem, the probability that 30% of the investors invest more than 1 million can be obtained as P[X≥1]=P [Z≥^P−P0 √P0(1−P0) n] ¿P [Z≥0.24−0.30 √0.30(1−0.30) 45] ¿P[Z≥−0.06 √0.004667]
15APPLIED QUANTITATIVE METHOD P[Z≥−0.8783] ¿P[Z<0.8783] ¿0.81 References Chatterjee, S. and Hadi, A.S., 2015.Regression analysis by example. John Wiley & Sons. Cox, D.R., 2018.Applied statistics-principles and examples. Routledge. Fisz, M. and Bartoszyński, R., 2018.Probability theory and mathematical statistics(Vol. 3). J. wiley. Rees, D.G., 2018.Essential statistics. Chapman and Hall/CRC.