Here, Median = 715 Mode The maximum repetition incurred for 401 and therefore, the mode of the data is 401. Question 2 (a)The given set of data would be categorised as sample not the population. This is because only the data for the seven weeks has been provided and the given data does not correspond to all the weeks for which the university is working. Hence, the data would be sample. (b)The standard deviation for weekly attendance 4
Sample size = 7 Total sum = 3392 Mean (x bar) = Total sum/ Sample size =3392/7 = 484.57 Standard deviation Standard deviation = 74.06 (c)IQR (inter quartile range) 5
(d)Calculation of correlation coefficient (r) 6
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Therefore, the regression line equation would Example to explain the regression equation ï‚·Holmes University has closed which there would be zero weekly attendance. ï‚·When number of students is increased to 10, then the total number of bars sold would also be enhanced by 1068 units that are same as 10 times number of coefficient of weekly attendance. (b) Calculation of coefficient of determination 8
93.70% of deviation in number of chocolate bars sold can be described by deviation in the weekly attendance. Question 4 Data and information is shown below: (a)Probability that a randomly chosen player is receiving grassroots training or is from Holmes University. (b)Probability that a randomly chosen player is receiving scientific training and is external. (c)Probability that a randomly chosen player is receiving scientific training and is from Holmes University. 9
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(d)The objective is to decide whether the two events training and recruitment are considered as independent variable. Condition of two events P and Q to be termed as independent events Let And, Result (e)Condition of two events P and Q to be termed as independent events are not satisfied and hence, training and recruitment cannot be considered as independent variable. Question 5 (a) 10
And, Bayesian Probability (b)Primary choice of customer will only be product X Question 6 (a)Probability that 2 or less than 2 customers will purchase from shop Binomial Distribution 11
Number of trials = 8 Probability of success = 0.1 (b)Probability that in 2 minutes total 9 customers will enter into shop Poisson distribution Question 7 (a)Probability that apartment will sell more than $2 million 12
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From Standard Normal Table (b)Probability that apartment will sell over $1 million but lower than $1.1 million From Standard Normal Table 13
Question 8 (a)For a given sampling distribution to be assumed as normal , it is imperative as per the CLT (Central Limit Theorem) that the sample size must be large and hence must be greater than 30. The given variable would be considered as normally distributed owing to the sample size being greater than 30. Therefore, z can be used as the suitable test statistics for checking the assistant’s findings. (b) Sample proportion Total investors = 45 Investors agreed to invest = 11 Standard error Among the investors, 30% of the investors are ready to participate to make the fund profitable and to commit an investment of $1 million or more into fund. From Standard Normal Table 14