Calculation of Quantities of Materials for Building Project 1

Verified

Added on  2023/04/08

|13
|1806
|173
AI Summary
This assessment involves calculation of quantities of materials of different elements of the building in project 1. There are nine tasks to be solved.

Contribute Materials

Your contribution can guide someone’s learning journey. Share your documents today.
Document Page
Running head: ASSESSMENT 2
ASSESSMENT 2
Name
Course
Professor
University
City/state
Date

Secure Best Marks with AI Grader

Need help grading? Try our AI Grader for instant feedback on your assignments.
Document Page
ASSESSMENT 2 2
Assessment 2
Introduction
This assessment involves calculation of quantities of materials of different elements of the
building in project 1. There are nine tasks to be solved.
The summary of take-off quantities of materials s provided in Table 1
1. Bore excavation for 300mm diameter piers
Diameter of piers = 300 mm
Depth of piers = 2.5 m
The piers are located at every corner/beam intersection and spaced at a maximum of 1800mm.
From the structural detail of the ground floor, the number of piers is 53.
The volume of one pier is calculated as follows: πr2h (where r = radius of the pier and h = depth
of the pier).
Volume = π x (0.15m)2 x 2.5m = 0.1767 m3
Total volume of bored excavation for 53 piers = 0.1767 m3 x 53 = 9.366 m3
2. Bulk excavation
This is done by removing vegetation and top soil not exceeding 300mm deep starting from the
existing ground level so as to prepare the site generally for laying the foundation and ground
floor slab. However, it does not include detailed excavation of the slab and beams. The bulk
excavation is done 1m beyond the house walls to create adequate working space. It is assumed
Document Page
ASSESSMENT 2 3
that the depth of bulk excavation is 300mm. The bulk excavation is measured from the structural
details.
The bulk excavation volume is determined by multiplying the length, width and depth of the
ground area to be excavated.
Some excavated material will be needed to be used as fill because of the ground is uneven as
shown by the contours in the building site plan. About half of the excavated material will be used
as fill to level the ground for the slab construction. Therefore the amount of fill material needed
is about 37m3.
3. N25 concrete for ground slab
The concrete for each of the elements on the ground is determined by multiplying the length with
the width and depth of that particular element as follows
Ground floor slab
6.3m x 5.17m x 0.1m = 3.26m3
5.18m x 5.17m x 0.1m = 2.68m3
6.3m x 5.16m x 0.1m = 3.25m3
5.18m x 5.16m x 0.1m = 2.67m3
3.63m x 4.61m x 0.1m = 1.67m3
Beams
Edge beams (EB):
2 x 12.83m x 0.45m x 0.42m = 4.85m3
Document Page
ASSESSMENT 2 4
1 x 10.97m x 0.45m x 0.42m = 2.07m3
1 x 10.82m x 0.45m x 0.42m = 2.04m3
2 x 3.63m x 0.45m x 0.42m = 1.37m3
Internal beams (IB):
1 x 11.48m x 0.35m x 0.35m = 1.41m3
1 x 10.97m x 0.45m x 0.35m = 1.73m3
1 x 4.61m x 0.45m x 0.35m = 0.73m3
Patio slab
5.17m x 0.35m x 0.1m = 0.18095m3
[(1.32m x 6.35m) – (0.35m x 0.24m)] x 0.1m = 0.8298m3
Pad footings
2 x 0.9m x 1.2m 0.45m = 0.972m3
4. SL72 reinforcing mesh for ground slabs
The net measure of SL72 reinforcing mesh is determined by calculating the net area of ground
floor slab and patio slab as follows
Ground slab:
11.93m x 10.97m = 130.87m2
3.63m x 4.61m = 16.73m2
Patio slab:

Secure Best Marks with AI Grader

Need help grading? Try our AI Grader for instant feedback on your assignments.
Document Page
ASSESSMENT 2 5
5.17m x 0.35m = 1.81m2
[(1.32m x 6.35m) – (0.35m x 0.24m)] = 8.3m2
Net ground area = 130.87m2 + 16.73m2 + 1.81m2 + 8.3m2 = 157.71m2
The number of sheets needed to complete the ground slabs is determined by dividing the net
ground area by the effective cover of one sheet. The effective cover of reinforcing mesh sheet is
5.8m x 2.2m with 400mm lap. Thus the number of sheets is calculated as follows
No . of sheets= Net ground area
Effective cover of a sheet = 157.71 m2
( 5.8 x 2.2 ) m2 =157.71 m2
12.76 m2 =12.36 sheets
5. SL12TM for ground slab
The length of trench mesh needed is determined by calculating the total length of trenches
needed for the ground slab. The trench lengths are determined as follows:
3 x 12.83m = 38.49m
3 x 10.97m = 32.91m
2 x 4.08m = 8.16m
1 x 4.61m = 4.16m
Total = 38.49m + 32.91m + 8.16m + 4.16m = 83.72m
6. Structural steel
The structural steel bars used are of diameter 12 mm and spaced at 200mm apart. The weight of
this bars is 0.89kg or 0.00089 tonnes per meter.
Document Page
ASSESSMENT 2 6
No . of main bars= Width of the slab
Spacing +1 CITATION Civ19 \l 1033 (Civilology, 2019)
Length of main bars = no. of main bars x length of one main bar (Hamakareen, 2018); (Krishna,
2019).
No . of main bars= 6200
200 +1=32 bars
Length of main bars = (32 x 5.11m) + (32 x 4.97m) = 163.52m + 159.04m = 322.56m
No . of main bars= 5080
200 + 1=27 bars
Length of main bars = (27 x 5.11m) + (27 x 4.97m) = 137.97m + 134.19m = 272.16m
No . of main bars= 3530
200 +1=19 bars
Length of main bars = (19 x 4.51m) = 85.69m
No . of main bars= 1220
200 + 1=8 bars
Length of main bars = (8 x 5.45m) = 43.6m
Total length of main bars = 322.56m + 272.16m + 85.69m + 43.6 = 724.01m
No . of distributionbars= Width of the slab
Spacing +1
Length of distribution bars = no. of distribution bars x length of one distribution bar
No . of distributionbars= 5450
200 +1=29 bars
Length of distribution bars = (29 x 6.2m) + (29 x 5.08m) = 179.8m + 147.32m = 327.12m
Document Page
ASSESSMENT 2 7
No . of distributionbars= 4970
200 +1=26 bars
Length of distribution bars = (26 x 6.2m) + (26 x 5.08m) = 161.2m + 132.08m = 293.28m
No . of distributionbars= 4510
200 +1=24 bars
Length of distribution bars = (24 x 3.63m) = 87.12m
No . of distributionbars= 5450
200 +1=29 bars
Length of distribution bars = (29 x 1.32m) = 38.28m
Total length of distribution bars = 327.12m + 293.28m + 87.12m + 38.28m= 745.8m
7. Plasterboard for first floor rooms lining
Net measure
The net measure includes the area of walls of the first floor rooms excluding wet areas. The
height of the first floor rooms is 2450mm.
Rumpus: 4.5m + 5.52m + 1.99m + 3.36m + 1.71m = 17.07m x 2.45m = 41.82m2
Gallery: 6.06m + 4.16m = 10.22m x 2.45m = 25.04m2
Bed 1: 10.54m + 8.12m = 18.66m x 2.45m = 45.72m2
Bed 2: 7.08m + 6.98m = 14.06m x 2.45m = 34.45m2
Bed 3: 3.54m + 3.23m + 2.14m + 2.22m + 2.15m = 13.28m x 2.45m = 32.54m2
Bed 4: 2.66m + 3.34m + 3.03m + 3.34m = 12.37m x 2.45m = 30.31m2

Paraphrase This Document

Need a fresh take? Get an instant paraphrase of this document with our AI Paraphraser
Document Page
ASSESSMENT 2 8
Net area of walls = 41.82m2 + 25.04m2 + 45.72m2 + 34.45m2 + 32.54m2 + 30.31m2 = 209.88m2
Number of plasterboard sheets
Standard size of plasterboards is 2400mm long and 1200mm wide. Area of one sheet is:
2.4m x 1.2m = 2.88m2
No . of sheets= Net areaof walls
Area of one sheet = 209.88 m2
2.88 m2 =72.88 73 sheet s
8. DAR pine skirting for first floor rooms
The length of skirting needed for the first floor rooms is as follows:
Rumpus: 4.5m + 5.52m + 1.99m + 3.36m + 1.71m = 17.07m
Gallery: 6.06m + 4.16m = 10.22m
Bed 1: 10.54m + 8.12m = 18.66m
Bed 2: 7.08m + 6.98m = 14.06m
Bed 3: 3.54m + 3.23m + 2.14m + 2.22m + 2.15m = 13.28m
Bed 4: 2.66m + 3.34m + 3.03m + 3.34m = 12.37m
Ensuite: 6.8m + 8.12m + 3.62m + 4.98m = 23.52m
Bath: 6.06m + 6.52m = 12.58m
Hall: 4.16m + 2.22m + 4.3m + 3.04m + 1.59m = 15.31m
Balcony: 11.04m + 3.04m = 14.08m
Total = 17.07+10.22+18.66+14.06+13.28+12.37+23.52+12.58+15.31+14.08 = 151.15m
Document Page
ASSESSMENT 2 9
The length of one skirting is 2.7m
No . of skirtings= Length of internal wall
Length of skirting = 151.15
2.7 m =56 pieces
9. Ceramic floor tiles
First is to calculate the floor area of the individual gro9und floor rooms
Family room: 4.08m x 5.03m = 20.52m2
Meals room: 2.17m x 4.589m = 9.96m2
Kitchen: 4.589m x 5.87m = 26.94m2
Foyer/stairs: 5.5m x 1.71m = 9.41m2
Net floor area = 20.52+9.96+26.94+9.41 = 66.83m2
Allow 10% wastage = 110
100 x 66.83 m2=73.51 m2
Size of tiles used is 20cm by 20cm
Area of one tile = 0.2m x 0.2m = 0.04m2
No of tiles = Total floor area
Area of one tile = 73.51m2
0.04 m2 =1837.75 1,838tiles
Table 1: Material quantities take-off
Ite
m
Particulars Unit Qnty Rate Cost
Document Page
ASSESSMENT 2 10
1 Bored excavation for 300mm diameter piers m3 10
53/π/0.15/0.15/2.5 9.37
2 Bulk excavation (excluding detailed excavation for slab and beams) m3 74
14.83/13.87/0.3 61.71
5.08/7.51/0.3 11.45
73.16
3 N25 concrete to the ground slab, beams, patio slab and pad footing m3 30
3.1 Ground floor slab
6.3/5.17/0.1 3.26
5.18/5.17/0.1 2.68
6.3/5.16/0.1 3.25
5.18/5.16/0.1 2.67
3.63/4.61/0.1 1.67 13.53
3.2 Edge beams
2/12.83/0.45/0.42 4.85
1/10.97/0.45/0.42 2.07
1/10.82/0.45/0.42 2.04
2/3.63/0.45/0.42 1.37 10.33
3.3 Internal beams
1/11.48/0.35/0.35 1.41
1/10.97/0.45/0.35 1.73
1/4.61/0.45/0.35 0.73 3.87
3.4 Patio slab
5.17/0.35/0.1 0.18
1.32/6.35/0.1 0.84
0.35/0.24/0.1 (0.0084) 1.01
3.5 Pad footings
2/0.9/1.2/0.45 0.97 0.97
29.71
4 SL72 reinforcing mesh to ground slabs
4.1 Net measure of ground slabs m2 158
11.93/10.97 130.87
3.63/4.61 16.73
5.17/0.35 1.81
1.32/6.35 8.38
0.35/0.24 (0.084)
157.71
4.2 Number of reinforcement sheets No 13
157.71/(5.8/2.2)-1 12.36
5 SL12TM m 84
3/12.83 38.49
3/10.97 32.91
2/4.08 8.16
1/4.61 4.16
83.72

Secure Best Marks with AI Grader

Need help grading? Try our AI Grader for instant feedback on your assignments.
Document Page
ASSESSMENT 2 11
6 Structural steel of ground floor t 1.31
6.1 Main bars t 0.65
32/10.08/0.00089 0.29
27/10.08/0.00089 0.24
19/4.51/0.00089 0.08
8/5.45/0.00089 0.04
0.65
6.2 Distribution bars
29/11.28/0.00089 0.29 t 0.66
26/11.28/0.00089 0.26
24/3.63/0.00089 0.08
29/1.32/0.00089 0.03
0.66
1.31
7 Plasterboard
7.1 Net measure m2 210
17.07/2.45 41.82
10.22/2.45 25.04
18.66/2.45 45.72
14.06/2.45 34.45
12.28/2.45 32.54
12.37/2.45 30.31
209.88
7.2 Number of plasterboard sheets no 73
209.88/(2.88)-1 72.88
8 66x18mm finished DAR primed pine skirting
8.1 Net measure m 152
Bed 1 18.66
Bed 2 14.06
Bed 3 13.28
Bed 4 12.37
Ensuite 23.52
Bath 12.58
Rumpus 17.07
Gallery 10.22
Hall 15.31
Balcony 14.08
151.15
Number of skirting pieces no 56
151.15/(2.7)-1 55.98
9 Ceramic floor tiles
9.1 Net floor area m2 74
Family room
4.08/5.03 20.52
Meals room
Document Page
ASSESSMENT 2 12
2.17/4.589 9.96
Kitchen
4.589/5.87 26.94
Foyer/stair
5.5/1.71 9.41
66.83/1.1 73.51
9.2 Number of tiles no 1838
73.51/(0.04)-1 1837.75
Document Page
ASSESSMENT 2 13
Works Cited
Civilology. (2019). How to Calculate Steel Quantity for Slab? – Reinforcement Calculation . Retrieved
from Civilology: http://www.civilology.com/bar-bending-schedule-for-slab/
Hamakareen, M. (2018). How to calculate steel quantity for slab, footing and column? Retrieved from
The Constructor: https://theconstructor.org/practical-guide/calculate-steel-quantity-slab-
footing-column/25533/
Krishna. (2019, January 12). Bar Bending Schedule [BBS] Estimate of Steel in Building Construction.
Retrieved from Civil Read: https://civilread.com/bar-bending-schedule-bbs/
1 out of 13
circle_padding
hide_on_mobile
zoom_out_icon
[object Object]

Your All-in-One AI-Powered Toolkit for Academic Success.

Available 24*7 on WhatsApp / Email

[object Object]