This document provides solutions for Assignment 3 Mat7603. It includes ratios, unknown terms, computations, and answers to various questions. The study material is relevant to the course Mat7603.
Contribute Materials
Your contribution can guide someone’s learning journey. Share your
documents today.
Assignment 3 Mat7603 Total Assignment 3 worth 54 marks = 5% of the overall course mark A. Set up a ratio for each of the following and reduce to lowest terms:(1.5 marks each: Total 3 marks) 1.15 hours to 3 days 15:(3∗24) Simplifying 15:72 2.$40 per day for 12 employees for 14 days Wage:Employees:time 40:12:14 Simplifying 20:6:7 B A student spends 20 hours per week in classroom lecture time, 45 hour per week in individual study time, and 5 hours per week travelling to and from school. What is the ratio that exists between the three times?2 marks. Lecture:Study:traversing 20:45:5 Simplifying 4:9:1 C. Find the unknown term in the following proportions. (1.5 mark each: Total 3 marks) 1.n : 7 = 24 : 42 n=24/(42/7) n =4 2.4 5: t =1 3:5 8 t= ((1/3)/ (4/5))/(5/8) t=2/3 D.
Secure Best Marks with AI Grader
Need help grading? Try our AI Grader for instant feedback on your assignments.
Material cost of a fan belt is five-eighths of the total cost, and labour cost is one-third of material cost. If labour is $15, what is the total cost of the fan belt? 3 marks. Costofafanbelt=5/8oftotalcost Labour=1/3ofmaterial Labour=$15 Materal=3∗15=$45 Totalcost=45+15 Costoffanbelt=5/8∗¿$37.5 E. Compute each of the following: (1 mark each: Total 3 marks) 1.0.02%of360=0.072 2.0.9%of3600=0.0324 3.3 4%of3600=2700 F. Use fractional equivalents to compute each of the following (round to a whole number (integer)): (1 mark each: Total 2 marks) 1.114 1/2 % of $460 = $526.7 2.20 2/3 % of $35 = $7.23 G. If total deductions on a yearly salary of $22,826 amounted to151 3%, how much was deducted? 2 marks. 15 1/3%,*$22,826=$3499.98 H. Jim’s four sons were to share equally in a prize, each receiving $19 each. How much was the total prize?1 mark. Let the prize be X ½ of x =$19 Therefore the price = $38
I. A company’s bad debt is $16,425 which is 41/2% of sales. What were the company’s sales?2 marks 41/2%=$16,425 100%=x X=($16,425*1)/0.045=$365000 J. Answer each of the following questions: (3 marks each: Total 33 marks) 1.How much is $12 increased by 300%? $12*300%=$36 2.What amount is131 3%less than $90? 131 3%*90=$12 90−12=$78 3.The amount of $100 is what percent more than $40? (100-40)/40=150% 4.What percent less than $600 is $594? (600−594)/600=1% 5.The number 110 is201 2%more than what number? 110*0.795=87.45 6.After an increase of 4%, the new amount is $139. What was the original amount? 104%=$139 100=x X=(1∗139)/1,04 ¿$133.65 7.A retail outlet is offered a discount of41 2% for payment in cash for an invoice of $912. If it accepted the offer, how much was the cash payment? Cash=100%−41 2% Therefore=95.5%∗912=870.96 8.Sales in July increased15%over June sales. If July sales amounted to $26,000, what were June sales? 115%=$26,000
100=x X=22608.70 9.In Montreal, a car sold for $17,394 including tax of 13%. How many dollars was the tax on the car? 17,394*0.13=2261-22 10.How many Canadian dollars can you buy for US$650 if one Canadian dollar is worth US$0.7271? 650/0.7271=CDN$893.962 11.What is the price of gasoline per litre in CDN dollars if a US gallon of gasoline costs US$3.12? One U.S. dollar is worth CDN$1.28 and one U.S. gallon is equivalent to 3.8 litres. 1gallon=us$3.12 1usd=CDN$1.28 Priceoagallon∈CDN$=3.12∗1.28=CDN$3.9936