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Graded Assignment

   

Added on  2022-12-29

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Running Head: ASSIGNMENT
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GRADED ASSIGNMENT
Name of the Student
School Affiliation.

ASSIGNMENT
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Graded Assignment
1. Which of the following statements is true concerning what happens when cold milk is poured
into hot coffee?
a. The cold milk transfers its cold to the coffee, cooling the coffee down.
b. The cold milk transfers its heat to the coffee, warming the coffee up.
c. The warm coffee absorbs the cold from the milk, cooling the coffee down.
d. The warm coffee transfers its heat to the milk, cooling the coffee down.
The correct answer is (d). The warm coffee transfers its heat to the milk, cooling
the coffee down.
The coffee will transfer its energy to the milk, milk will, therefore, gain heat energy.
Both teaching equilibrium by attaining the same temperature.
The law of conservation of energy states that ‘'Energy is conserved, it cannot be created
or destroyed but can be only be changed from one form to another. If no energy is
allowed to enter or leave the system, the total energy of the system remains constant’’
2. Convert 60ºC to Kelvin.
273.15 K is equivalent to 0ºC
Formula: T (K) = T (ºC) + 273.15
Temperature (K) = 60 (ºC) + 273.15 = 333.15
Temperature= 333.15 K

ASSIGNMENT
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3. What is the importance of the absolute zero?
Absolute zero is the lowest possible temperature (0 K) which is theoretical. It is
important in thermodynamics because of molecular motions theoretically.
4. For each of the following, indicate if the statement is describing an endothermic or
exothermic situation.
a. Endothermic energy is absorbed from the surrounding.
b. Exothermic (- H)
c. Endothermic products have more energy than reactants.
d. Endothermic (+ H)
e. Exothermic have more energy than the products.
f. Exothermic energy is released to the surrounding.
5. Solve the following problems.
a. A silver bar with the mass 150 grams is heated 24.5ºC to 60.5 ºC. how much heat
energy does silver bar absorb? The specific heat of silver is 0.235 J/g/ºC
Heat absorbed= mass (m) *specific heat capacity * temperature change
Heat absorbed= 150 (g) * 0.235 (J/g/ºC) * (60.5-24.5) ºC=1269.0 J
Heat absorbed=1269.0 Joules
b. A sample of gold absorbs 34.6 J of energy as its temperature is increased by 62.0
ºC .what is the mass of the gold sample. The specific heat of gold is 0.129 J/g/ºC
Heat absorbed= mass (m) *specific heat capacity * temperature change

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