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Assignment on Physic Electricity

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Added on  2021-04-24

Assignment on Physic Electricity

   Added on 2021-04-24

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Physic Electricity 1PHYSIC ELECTRICITYBy NameCourseInstructorInstitutionLocationDate
Assignment on Physic Electricity_1
Physic Electricity 2Assignment # 11.Vt= 120 V Pt= P1= 1200WattsȠ= 0.9 a) From P= VII= PV = 1200120 = 10 A Total current =10 A b) Total output power is given by the following equations pOUT = Pt×ȠpOUT = 1200×90100pOUT = 108000/100pOUT = 1080 watts c)Resistance in each conductor Power loss = 1200 -1080 Power loss= 120 Watts And from Rc= VtPlossRc= 120120 = 1Ω Therefore for each conductor the resistance will be ½ = 0.5 Ω2.When Rc = 0 Ω a)P=V2R
Assignment on Physic Electricity_2
Physic Electricity 3R=V2P= 12021200R=14400120R= 12 Ω b)The total resistance from the circuit diagram is given by Rt= R1+R2||R3 Rt= R1+R2R3R3+R2 = 12 But R1=R2=R3 Therefore R+R22R = 12 2R2+R2= 24 R R= 8 Ω Therefore R1=R2=R3 = 8 Ω c)V1Current through R1 is 10 A Therefore from V= IR V= 10 × 8 V1= 80 Volts d)Total resistance for R2 and R3 can be given by the following equation 1R23 = 1R2+ 13
Assignment on Physic Electricity_3

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