Basic Business Statistics Questions and Answers 2022

University
Basic Business Statistics
By
Your Name
Date
Page 1 of 19
© <Your Name> 2020

Solutions
Question 1
Part 1.1
1.1.1
To solve
( 32 ) 3
x ( 2 x 35 )
−2
x ( 18 ) 2
Solution
Apply exponent rule ( ab )c
=abc for the first term
( 32 ) 3
=32 x 3=36
For the second term we have:
( 2 x 35 ) −2
= 1
( 2 x 35 ) 2 = 1
22 x 35 x 2
¿ 1
23 x 310
The third term we simplify using powers
( 18 )2= ( 32 x 21 ) 2
=34 x 22
Putting everything together:
(36 )x ( 1
22 x 35 x2 ) x (34 x 22 )
Page 2 of 19
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Collecting the like terms
(36 x 34 )x ( 1
22 x 35 x 2 )x 22
But ( 36 x 34 ) =310 and 35 x2=310 hence
( 310 x 22
22 x 310 )=1
1.1.2
To solve
( ( 2 x 3
9 ÷3 )
−2
( 9
4 ) 2
x ( 2
5 )
−1
)
−1
Solution
Solve the numerator
( 2 x 3
9 ÷ 3 )
−2
= 1
( 2 x 3
9 ÷ 3 ) 2 = 1
( 2
9 )
2 = 92
22 = ( 9
2 )
2
Solving the denominator
( ( 9
4 )2
x ( 2
5 )−1
)=
(( 9
4 )2
x 1
( 2
5 ) )=
( ( 9
4 )2
x 5
2 )
Page 3 of 19
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Putting them together
( ( 9
2 )2
( ( 9
4 )2
x 5
2 ) )−1
=
( ( 81
4 )
( 81
16 x 5
2 ) )−1
=
( ( 81
4 )
(( 405
32 ) ) )−1
= ( 81
4 x 32
405 )−1
¿ ( 8
5 )
−1
= 5
8
Ans= 5
8
Part 1.2
Solution
The weights of the assignment, midcourse and final exam are 20, 25, and 55
respectively. To find the weighted score, we use the formula shown in the
table
Test Score Weight Score x weight
Assignment 52/60 20 17.33
Mid-course exam 48 /100 25 12
Final exam 155/2000 55 4.26
Weighted score
(/100)
33.59%
Page 4 of 19
© <Your Name> 2020