Bending Moments & Shear Forces with Beam Design Considerations - Desklib

BENDING MOMENTS & SHEAR FORCES WITH BEAM
DESIGN CONSIDERATIONS
HNCB 20- PRINCIPLES OF STRUCTURAL DESIGN
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Table of Contents
Task 1...............................................................................................................................................4
Task 2.............................................................................................................................................16
Task 3.............................................................................................................................................20
Task 4.............................................................................................................................................22
Reference list.................................................................................................................................26
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Task 1
1 (A)
A
Given data
L = 14m [Length of beam]
P = 150KN [Point load on Beam]
Taking moment from A
(150*7) + (-RB*14) = 0
1050 – 14 RB = 0
14 RB = 1050
RB = 1050/14
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RB = 75 ------------- [1]
Summation of upward force and downward force
RA – 150 +RB = 0
RA = 150 – 75
RA = 75 KN -------- [2]
Calculation of Shear force
FA = 75 KN
FB = 75-150 = -75 KN
FC = -75 KN
Calculation of bending moment
MA = 0
MB = 75*7 = 525 KN.m
MC = 0
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B
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Taking moment from A
- (65*2) +RB*8 = 0
8RB = 65*2
RB =16.25
Summation of all forces
RA – 65 + 16.25 = 0
RA = 48.75KN
Shear force
FA = 48.75
FC = -16.25
FB= -16.25
Bending moment
MA = 0
MC = 48.75*2 = 97.5 KN
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