Assignment on Business Statistics in Organization
Added on 2020-04-07
11 Pages1850 Words39 Views
Business StatisticsName of the StudentName of UniversityAuthor Note
Answer to Q1:Part a:Sample mean of left handed spatula:=3.5123+3.5132+3.5133+3.5127+3.5127+3.51236=21.0765/6=3.51275Part b:Sample mean of left handed corkscrew:=2.9834+2.9833+2.9834+2.9834+2.9838+2.98376=17.901/6=2.9835Part c:Sample mean of left handed meat tenderizer:=3.5213+3.5212+3.5212+3.5213+3.5212+3.52146= 21.1276/6= 3.521267Part d: Sample mean of left handed Cheese Grater:=4.0002+4.0003+4.0001+4.0003+4.0002+4.00036=24.0014/6=4.000233Answer Q2:Part a:Population mean: ∑xi/n2222.0122.0122.0221.982222.0122.012222.0121.9821.9922.0122.0222.032221.9921.972222.01
∑xi440.05n20∑xi/n22.0025Part b:Sample Mean: ∑xi/n222221.9722.0122.0121.9922.0321.99∑xi176.00n8∑xi/n22.00Part c:Sample error: Standard deviation of the statistic/ sqrt(n)222221.9722.0122.0121.9922.0321.99Stdev0.02n8SE0.01Answer Q3:Part a:Sample mean: ∑xi/nSample ItemWrench Opening Width14.5624.5634.5544.4954.5564.5674.5784.4894.58104.48∑xi/n4.538Part b:Sample distribution:
According to the theorem 6-1, the sampling distribution x-bar is defined as μ as center andσ/sqrt(n) as spread.Sample ItemWrench Opening Width14.5624.5634.5544.4954.5564.5674.5784.4894.58104.48shape ( )= ∑xi/nμ4.538spread ( /sqrt(n))σ0.012274635Part c:Even of Interest:Here, the aim is to understand whether the wrench machine needs to be recalibrated ornot. Thus, the event is “Wrench machine needs to be recalibrated.”Null hypothesis (H0): There is no need for wrench machine recalibration [>4.56]μAlternative hypothesis (H1): There is a need for wrench machine recalibration [ <=4.56]μPart d:Standardized z value: (X-bar – 4.56)/(σ/sqrt(n))= (4.538-4.56)/( 0.012274635)=-1.79231Part e:Desired probability: 0.0365 = 3.65%Since, p value is less than 0.05, it can be said that the null hypothesis will be rejected here.Thus, it can be concluded that there is a need for wrench machine recalibration.Answer Q4:Part a:Sampling distribution: the sampling distribution x-bar is defined as μ as center andσ/sqrt(n) as spread.Here, = 32.78μ = 8.17σ
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