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F100 - Chemistry - Experiment on Titration

   

Added on  2020-03-04

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Running head: CHEMISTRY 0CHEMISTRYName of StudentInstitution Affiliation

CHEMISTRY 2Experiment: PREPARATION OF SODIUM CARBONATE SOLUTION AND ACID-BASE TITRATIONMaterials used Solid Sodium Carbonate,Distilled Water Diluted Hydrochloric acid Phenolphthalein indicator PART A: PREPARATION OF SOLUTIONI.OBJECTIVES To prepare accurately a solution of sodium carbonate Na2CO3, starting with a pure solid sodium carbonate.II.BACKGROUNDAnhydrous sodium carbonate of analytical reagent quality can be used as a primary standard as itcan be obtained very pure and does not readily pick up moisture from the air. By dissolving a precisely known mass of Na2CO3 in a definite volume of solution, it is possible to prepare a standard solution of Na2CO3 that is one whose solution is known exactly[ CITATION Mar121 \l 1033 ].

CHEMISTRY 3PROCEDURE Weighing boats 1.3g to 1.4 g of Na2CO3 were accurately weighed and the correct weighed amount was noted down. 100 mL volumetric flask was rinsed clean with a reasonable amount of distilled water[ CITATION Joh141 \l 1033 ]. Sodium carbonate was transferred into this volumetric flask using a spatula or a filter funnel. Solid Na2CO3 with distilled water in volumetric flask was dissolved and the flask was filled to approximately a quarter full with distilled water then stopperwas used and it was shaken well to enable it to dissolve. Distilled water was added to just below the calibrated mark. Pasteur pipette was used to add the final volume of water drop- wise so that the bottom of the meniscus is on the calibration line[ CITATION Nor13 \l 1033 ]. The stopper of the flask was inverted 15 times so that the solution is homogeneous and the solution was labeled. Calculating the concentration of the prepared solution. Mass of the Na2CO3 = 1.4 gMolar mass of Na2CO3 = 106 Number of moles of Na2CO3 = MassofNa2CO3molarmassofNa2CO3Number of moles = 1.4106 = 0.0132 moles Concentration of Na2CO3 (grams/liter) = gramsofNa2CO3volumeofthesolution(L)

CHEMISTRY 4 Concentration in grams per liter =1.40.025 (¼ of 100 mL)Concentration of Na2CO3= 56 g/ liter Concentration of Na2CO3 (moles/liter) = molesofNa2CO3volumeofthesolution(L)Concentration in grams per liter =0.01320.025Concentration of Na2CO3 = 0.5283 M (moles / liter) Concentration of Na2CO3 (ppm) = gramsofNa2CO3mgvolumeofthesolution(L)Concentration in ppm =0.00140.025Concentration in ppm = 0.056 Concentration of Na2CO3 ( ppb) = gramsofNa2CO3μgvolumeofthesolution(L)Concentration in ppb =0.00000140.025

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