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COIT20261 - Network Routing & Switching

   

Added on  2021-04-17

4 Pages1052 Words42 Views
COIT20261 Network Routing and Switching (Term 1, 2018)Assignment item —Written Assessment-1First Name: _________________________Last Name: _________________________Student ID: __________________________Question NumberMarkallocatedMark earnedQuestion 1: (3 marks)3a)b)c)The network address for the classless address block of 154.78.177.3/27 is 154.78.177.0/27Binary representation of the IP address - 10011010.01001110.10110001.000 00011Binary representation of subnet mask- 11111111.11111111.11111111.111 00000Network address - 10011010.01001110.10110001.000 00000For the calculation of the network address the address block isconverted into binary notation, then the subnet is calculated byperforming a bit wise AND operation on the host address and thesubnet. The subnet address is found for adding the hosts. The direct broadcast address for the classless address block 154.78.177.3/27 is 154.78.177.31. The broad cast address is identified by all the 1s.10011010.01001110.10110001.000 11111The range available for the hosts to use starts from 154.78.177.1 to 154.78.177.30For finding the range of the IP address the first host is calculated using the by identifying all the 0s and a 1 and for finding the last host all 1s and a 0 is used. 1 mark each item, total 3Question 2: (8 marks)8a)Address - 138.77.216.5 /24Network address of the block – 138.77.216.0Binary conversion of 138.77.216.510001010.01001101.11011000 .00000101Binary of the subnet mask 255.255.255.011111111.11111111.11111111 .00000000The network address10001010.01001101.11011000 .00000000138.77.216.0 /241b)SubnetNo. addressesSubnet addressMask /n132138.77.216.0/26232138.77.216.64/26316138.77.216.128/276

COIT20261 Network Routing and Switching (Term 1, 2018)Assignment item —Written Assessment-1416138.77.216.160/27516138.77.216.160/27616138.77.216.224/27c)It is not possible to create another subnet for assigning more 1024 address tothe network address 138.77.216.0 /24. For the /24 subnet 254 maximumnumber of hosts can be accommodated and among them 128 number of IPaddress are allocated to the six different subnet. There are 126 number of IPaddress remaining that is insufficient because the requirement is 1024addresses. 1Question 3: (4 marks)4a)i)ii)iii)iv)The interface of the wireshark is divided into three horizontal window and thefirst part contains the list of data packets that are captured by selecting thestart capture option in the menu bar of wireshark. The time, source,destination, protocol, length and the information is described in the firsthorizontal window. The second section consists of details of the packet and itprovides the details of the packet that is selected from the first section of thewindow. Lastly, the third section provides the details of the content in rawdata format and it is known as the packet byte pane. From the frame 3 the brand of the computer used for launching the scan andthe IP address of the computer can be identified. The brand identified isHewlett and the IP address of the computer was 138.77.216.88. The details ofthe computer and the IP address can be found from the packet details sectionand expanding the Ethernet II option and the IPv4 address.Frame 4- A hello message is sent from the server to the client Frame 5 – The digital certificate is verified at the clients end and Frame 6 – Server hello message done is sent from the server to the client The two specific network problem that can be troubleshooted using the wireshark tool are given below:a.Identification of the source of the errors in the networkb.Identification of the source of traffic in the network and blockthe host for securing the network..5 mark each item, total 2 for 3a.b)Description of the column heading of ‘NETSTAT –aon’ Proto – It defines the protocol used for the transmission of the data in thenetworkLocal Address, Foreign Address – It is used for the listing the source and thedestination address between whom the data is sent in the network. The localaddress is given for the host running the NETSTAT command and foreignaddress is for the other nodes connected in the network. State – It is used for demonstration of the socket state.PID – It shows the process ID and it can be used for finding the owner of the1

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