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COIT20261 Network Routing and Switching Term 1, 2018 Assignment

   

Added on  2021-05-31

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COIT20261 Network Routing and Switching (Term 1, 2018)Assignment item —Written Assessment-2First Name:_________________________Last Name:____________________________Student ID: __________________________Question NumberMarkallocatedMarks earnedQuestion 1: (10 marks)1.2.3.4.5.6.7.8.For the router R4 150.3.0.2 is the next hop address for the packet addresses to host 161.22.0.15/18For the router R1 the interface used for sending the data to the network 161.22.0.0/18 is M2.When a packet is sent between 200.11.60.36 /24 and 150.32.0.240 /18 aminimum 2 hops needs to be travelled for reaching the destinationlocation. If a data packet generated from the source 200.11.60.36 /24 reaches therouter R1 and the router does not finds the destination address in therouting table it drops the data packet. If a data packet with the destination address 140.21.0.10/22 reaches therouter R2 the interface M0 is used for forwarding the data packet.The destination address of a packet at router R3 is 220.10.40.5 /24 the next hop address for sending the data packet would be 150.3.0.3 /16For the data packet waiting on the router R4 and if the next hop is a direct delivery the network 150.3.0.0 /16 is the destination network. q.8 Routing table of router R2:PrefixNetwork addressNext-hop address Interface255.255.255.0220.10.40.0150.3.0.3M0255.255.255.0200.11.60.0200.21.60.1M1255.255.252.0140.21.0.0140.21.0.1M2255.255.192.0161.22.0.0150.3.0.3M0255.255.192.0150.32.0.0150.3.0.1M0255.255.0.0150.3.0.0150.3.0.2loopback1-7 1 mark each, q.83 marksQuestion 2: (5 marks)a)IP datagram = 5400 bytesMTU = 1500 bytesIP header = 20 bytes2.5

COIT20261 Network Routing and Switching (Term 1, 2018)Assignment item —Written Assessment-2Therefore, 5400 -20 = 5380MTU of 1500 bytes, 1500 -20 = 1480 bytes of data is transmitted for eachof the data packetsCeiling (5380 /1480) = 4 packets are required1st packet: 20 bytes: IP header, 1480 bytes: Data ==> Correct size: 20+1480 = 1500 bytes, starting byte :1 , ending bytes : 14802nd packet: 20 bytes: IP header, 1480 bytes: Data ==>Correct Size: 20 +148 = 1500 bytes, starting bytes : 1481, ending bytes : 29603rd packet: 20 bytes: IP Header, 1480 bytes: data ==>Correct Size: 20+1480 = 1500 bytes, starting bytes :2961, ending bytes: 44404th packet: 20 bytes: IP Header, 1345 bytes: Data ==>Correct size: 20 +1345 = 1365 bytes, starting bytes: 4441, ending bytes: 5805b)Offset value of the 1st packet fragmentation = 0Offset value of the 2nd packet fragmentation = 185Offset value of the 3rd packet fragmentation = 370Offset value of the 4th packet fragmentation = 5551.5c)20 bytes is consumed by the header byte of the data packet and it is samefor all the data packets transferred in then network. If the total size of thedatagram packet is 1500 the starting byte of the second packet is 1480byte and thus the total byte sent is less than the initial size of the datagramthat arrives in the router.1Question 3: (10 marks)1.Reno and CUBIC are the two different clog control mechanism that areused in TCP and it is covered in the unit. The unit also describes about thecurrent BBR algorithm developed by Google for speeding up the internetand optimizing the rate of delivery of the data packets in the currentnetwork using the TCP clog control mechanism. For the optimization ofthe delivery of the data packets it is important to identify the round triptime and the bandwidth and sending the data packets at a rate that doesnot causes congestion in the network. For avoiding the bottlenecksituation different buffers are used and a network model is created for theselection of the best path in the network. 12.The application of the buffer in the network can increase the delay forsending and receiving the data packets with the formation of unnecessaryqueue in the network. The application of the shallow buffers in the lossbased congestion network can impact the network as it can decrease thesending rate of the data packet. The application of the deep buffer cangenerate an unnecessary que as it is repeatedly filled with the last milelink of the network. 23.The BBR and the TCP protocol are used for controlling the congestion inthe network using the TCP/IP protocol but both follows differentmechanism for controlling the loss and the congestion. The BBRalgorithm utilizes an optimized speed for sending the packets by creatinga network model and finding the best path and calculating the round triptime. The path is selected and the data packets are sent at a rate that would3

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