Computer Organization and Architecture - Desklib

Running head: COMPUTER ORGANIZATION AND ARCHITECTURE
Computer Organization and Architecture
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COMPUTER ORGANIZATION AND ARCHITECTURE
Answer to Question 1:
a) Given (152) x= (6A) 16
 X2 + (5 * X1) + (2 * X0) = (6 * 161) + (10 * 160)
 X2 + 5X + 2 = 106
 X2 + 5X - 104 = 0
 X2 + 13X - 8X – 104 = 0
 X(X + 13) – 8(X + 13) = 0
 (X - 8) (X + 13) = 0
 X = 8 and X = -13
Since, the value of X cannot be negative; so value of X is 8
(152)8= (6A) 16
b) i) BED = (B * 162) + (E * 161) + (D * 160)
= 2816 + 224 + 13
= (3053)10
(3053)10 =
Divider Dividend Remainder
3 3053 2
3 1017 0
3 339 0
3 113 2
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COMPUTER ORGANIZATION AND ARCHITECTURE
3 37 1
3 12 0
3 4 1
1
BED16 = (11012002)3
ii) (321)7 = (3 * 72) + (2 * 71) + (1 * 70)
= (162)10
So, (162)10 =
Divider Dividend Remainder
2 162 0
2 81 1
2 40 0
2 20 0
2 10 0
2 5 1
2 2 0
1
(162)10 = (10100010)2
iii) Conversion
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