Computer Organization and Architecture - Solved Assignments

Running head: COMPUTER ORGANIZATION AND ARCHITECTURE
Computer Organization and Architecture
Name of Student:
Name of University:
Author’s Note

1COMPUTER ORGANIZATION AND ARCHITECTURE
Answers to question number 1:
a)
Let us consider the base to be Y,
Given,
(152) Y = (6A) 16
Or, Y2 + 5Y + 2*Y = 6*16 + A
Or, Y2 + 5Y + 2*Y = 6*16 + 10
Y2 + 5Y + 2 = 106
Y2 + 5Y- 104 = 0
Y2 + 13Y- 8Y – 104 = 0
Y (Y + 13) – 8(Y + 13) = 0
(Y - 8) (Y + 13) = 0
Y = 8 and Y = -13
Hence, the value of Y is 8.
The value of the base is 8.
b)
Conversions:

2COMPUTER ORGANIZATION AND ARCHITECTURE
i) BED16 converting to base-3
= B * 16*16 + E * 16 + D
= 2816 + 224 + 13
= (3053)10
(3053)10 =
So, (BED)16 = (11012002)3
ii)
(321)7 = (3 * 72) + (2 * 71) + (1 * 70)
= (162)10
Again, (162)10 =