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Construction & Project Management Q1) Q2) i)Critical path: activities with zero slack of head event and zero slack for tail event A => C => E => G ii)Completion time = 2 + 2 + 4 + 5 = 13 iii)Variance =σ2p=(2 6) 2 +(2 6) 2 +(4 6) 2 +(5 6) 2 =1.3611 Q3a) ActivityActivity timeESEFLSLFLS-ES A6064104 s1,8 3,16 2,12 7,12 12,12 16,9 15,4 F 4,95,4 9,910,4
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B8152315230 C3232623260 D6263226320 E661310163 F7132016233 G505101510 H8515152310 I2131518103 Completion time = 32 weeks Total cost =£198,000 Cost on CP =£180,000 Number of critical path = 1 Critical path = B => C => D 3b) Crash ActivityActivity timeESEFLSLFLS-ES A404373 B448480 C2171917190 D4192319230 E47119132 F6111713197 G34710136 H671313196 I21113794 Completion time = 23 weeks Total cost =£316,000 Cost on CP =£296,000 Number of critical path = 1 Critical path = C => D The project would take between 32 and 23 weeks depending on the activity completion time that vary between the normal time and the crash time.
Crashing activity B by a week an additional cost of 6,000 would be incurred Crashing activity C by a week an additional cost of 2,000 would be incurred Crashing activity D by a week an additional cost of 3,000 would be incurred The best choice would be to crash an activity having the lowest incremental (additional) cost – therefore, in this case we would choose to crash activity C by one week at an additional cost of 2,000