CONVECTIVE HEAT TRANSFER.

Running head: CONVECTIVE HEAT TRANSFER
CONVECTIVE HEAT TRANSFER
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CONVECTIVE HEAT TRANSFER 2
Question 9.2
Air velocity = 0.65 √ gldt
273+te
Where g is the gravitational acceleration
L is the vertical distance
Dt is ts – te
ts is the uniform surface
te is the air temperature
V= 0.65 √ 9.81∗0.2∗30
273+ 40
V= 0.65 √ 58.86
313
V=0.65*0.43364
V=0.29197 m/S
Question 9.6
Q= [ π D2 h(T p−Tw ) ]
And from Re= ρ D
μwater we can obtain the value of D
Where ρ is the density of water.
D is the diameter
μwater Is dynamic viscosity = 8.9*10 -4
Q is the mean heat transfer
Tw is the temperature of water
Tp is the temperature of the plate