Data Analysis and Forecasting for Temperature of Nottingham City UK
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This report presents statistical analysis and linear forecasting model for temperature data of Nottingham city UK for last ten days. The report also forecasts the temperature of 12th and 14th day using linear forecasting model.
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DATA ANALYSIS AND FORECASTING
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Table of Contents INTRODUCTION...........................................................................................................................3 MAIN BODY...................................................................................................................................3 Temperature of Nottingham city UK-..........................................................................................3 Presentation of data in chart -......................................................................................................4 Statistical calculations-................................................................................................................4 Linear forecasting Model-............................................................................................................6 Forecasting of the temperature of 12th and 14th day-.................................................................8 CONCLUSION................................................................................................................................8 REFERENCES................................................................................................................................1
INTRODUCTION Data analysis and forecasting refers to the act in which the given data will be processed for the purpose of deriving conclusion from it and making most rational predictions with this regard. The report will be calculating a few statistical notions taking hypothetical temperature data and by applying linear forecasting model the asked data will be forecasted (Xia, 2018.) MAIN BODY Temperature of Nottingham city UK- DateTemperature(In Fahrenheit ) 1/02/202243 2/02/202242 3/02/202242 4/02/202244 5/02/202243 6/02/202243 7/02/202243 8/02/202243 9/02/202243 10/02/202241
Presentation of data in chart - Statistical calculations- (1) Mean- Mean = Sum of items/ Number of items Sum of items= 43+42+42+44+43+43+43+43+43+41 = 427 Number of items= 10 Value of mean= 427/10= 42.7 F
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For figuring out the mean of the given temperature the data is firstly summed up and then divided by the Number of items, in this case which is ten. The average or Mean of the temperature is 42.7, which cites that the average temperature of the city in ten days has been 42.7. (2) Median- data are arranged in ascending order= 41,42,42,43,43,43,43,43,43,44 Median formula = (N+1)/2thitem N= Number of observations = 10 = (10+1)/2thitem =5.5thitem = 43+43/2 Median= 43 The median of the given temperature is 43, which cites that the mid value of the temperature is 43 means the half temperature data would be above it and at the same time half would be below. Since it is the prime duty of median to divide the series in two equal parts where one half will be above and one half will be below the median value (Kihlblom Landtblom, 2018.) (3) Mode= It is the individual series so we will be using observation method for calculating Mode. Mode= In the given observations the number with highest frequency will be the mode. Mode= 43 Since by normal observation it is figured out that the number 43 is being repeated for six times. That's why it is considered Mode of the series. Mode express the understanding that in Nottingham the highest frequency of the temperature is 43 in the last ten days. (4) Range= Range= Maximum value- Minimum value 44- 41 Range= 3
Range signifies the value which express the range or diaspora of the given series. Which tells the difference between maximum and minimum value. It also shown that what is the maximum variability of the series. Here the range is 3, which explains that the temperature of Nottingham in last ten days was not too much varying rather it was floating in the range 3 (Huang, 2021.) (5) Standard deviation= xMean(x-mean)(x-mean)^2 4342.70.30.09 4242.7-0.70.49 4242.7-0.70.49 4442.71.31.69 4342.70.30.09 4342.70.30.09 4342.70.30.09 4342.70.30.09 4342.70.30.09 4142.7-0.72.89 N=106.1 Standard deviation= total of (x- mean) ^2 /(N) = 6.1/10 = 0.61 = under rood of 0.61 Standard deviation= 0.78102 standard deviation is the tool which measures that how dispersed the data is in relation to the mean of the series. If it is close to zero that refers that the data is pointed close to the mean of the series (Harrisson, 2018.)
Linear forecasting Model- y= mx + c XDateYXYx^2 11/02/202243431 22/02/202242844 33/02/2022421269 44/02/20224417616 55/02/20224321525 66/02/20224325836 77/02/20224330149 88/02/20224334464 99/02/20224338781 1010/02/202241410100 554272344385 Calculation of m- m = m= (10*2344) - (55*427)/ (10*385) - (55) ^2 = (23440) - (23485)/3850-3025= = -45/825 m= -0.0545 m is the slope of the line or it can also be defined as the gradient which defines the slope of the line. For forecasting it is quite significant notion. Here in this case the value of m is figured out by applying the given formula. The value of m is -0.0545 which explains that the slope is negative then the relationship between factor X and Y would be adverse in nature. If X will be increased, then the value of Y will be falling down due to adversity in relationship.
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Calculation of C= C= = 427-(-0.0545*55)/10 = 427-(-2.99)/10 C= 43 here the value of C is calculated by applying the given formula. In linear forecasting model C is a constraint value which can also be defined as intercept of Y. while calculating the value of variable Y, the intercept c will be considered a constraint and will be summed up directly in the calculated value. Since c is a constraint here which is defining the straight line of the linear forecasting diagram (Ciulla and D'Amico, 2019.) Forecasting of the temperature of 12thand 14thday- Here the formula of linear forecasting method will be applied and the temperature of the asked days will be calculated. 12thday- y=mx + c = -0.0545*12+43 = 42.346 the temperature of the day 12 would be 42.346F. The formula where Y is the dependent factor and X is independent factor, m is representing slope of line which is negative in this case and c which is constraint or intercept of y. The value of Y which is derived by these factors. 14thday- y= mx + c = -0.0545*14+43 = 42.237 the temperature of the day 14 would be 42.237. Which is lower than the temperature of 12thday. Since as it is mentioned earlier the factor m is negative, which cites that if we will hike the value of variable x then the y would get lower.
CONCLUSION In the report temperature data are taken for last ten days of Nottingham and then couple of statistical formulas are applied in order to analyse it. Further-more the linear forecasting model is applied for the purpose of forecasting the temperature of asked days. The report has presented the taken data in a chart form for making it more receptive.
REFERENCES Xia, X., 2018. DAMBE7: New and improved tools for data analysis in molecular biology and evolution.Molecular biology and evolution. 35(6). pp.1550-1552. Kihlblom Landtblom, K., 2018. Prospective Teachers’ Conceptions of the Concepts Mean, Median and Mode: Selected Papers from the 22nd MAVI Conference. Huang, 2021. A Double-PLLs-Based Impedance Reshaping Method for Extending Stability Range of Grid-Following Inverter Under Weak Grid.IEEE Transactions on Power Electronics.37(4). pp.4091-4104. Harrisson, S., 2018. The downside of dispersity: why the standard deviation is a better measure of dispersion in precision polymerization.Polymer Chemistry.9(12). pp.1366-1370. Ciulla, G. and D'Amico, A., 2019. Building energy performance forecasting: A multiple linear regression approach.Applied Energy.253.p.113500.