DC Networks - Electrical and Electronic Principles.

DC Networks - Electrical and Electronic Principles
Physics
Student Name:
Instructor Name:
Course Number:
19 April 2019

Question 3
i) For resistors R1 ,R2 and R3
1/R=1/20 + 1/60 +1/10 = 10/60
R= 60/10 = 6 Ω
For R4 and R5
60× 660
660 =54.55 Ω(Product over sum)
Total resistance is 6 Ω+54.55 Ω+( 2×1000) Ω
=2060.55 Ω
ii) V=IR (Ohm’s law)
3=2060.55 I
I= 3
2060..
=0.001456 A
iii) V1=IR
=0.001456×6
=0.008737 V
V2 =IR
=0.001456×54.55
=0.074248 V
V3=IR0.001456×2000
=2.912 V
iv) Current through R5 = 60
660 ×0.001456 A

=0.0001324 A
Circuit B
Circuit A (1N4148 Diode) in forward bias
V1 0.1V 0.2V 0.3V 0.4V 0.5V 0.6V 0.7V 0.8V 0.9V 1.0V 1.1V 1.2V
VD 0.1V 0.2V 0.3V 0.4V 0.5V 0.6V 0.7V 0.8V 0.9V 1.0V 1.1V 1.2V
ID 0.0001
V
0.0002V 0.0003V 0.0004V 0.0005V 0.000
6V
0.000
7V
0.000
8V
0.000
85V
0.000
96V
0.000
96V
0.000
98V
Circuit A (1N4148 Diode) in reverse bias
V1 2V 4V 6V 8V 10V 12 V
VD -2 V -4V -6V -8V -10V -12V
ID -0.002 A -0.004A -0.006A -0.008A -0.0086A -0.0088A
Circuit B (BAT54 Diode) in forward bias
V1 0.1V 0.2V 0.3V 0.4V 0.5V 0.6V 0.7V 0.8V 0.9V 1.0V 1.1V 1.2V
VD 0.1V 0.2V 0.3V 0.4V 0.5V 0.6V 0.7V 0.8V 0.9V 1.0V 1.1V 1.2V
ID 0.0001V 0.0002V 0.00
03V
0.00
04V
0.00
05V
0.00
06V
0.00
07V
0.00
08V
0.00
09V
0.00
095V
0.00
095V
0.00
096V
Circuit B (BAT54 Diode) in forward bias
V1 2V 4V 6V 8V 10V 12 V
VD -2V -4V -6V -8V -10V -12 V
ID -0.002 A -0.004A -0.006A -0.008A -0.0082A -0.084A