STATISTICS2Answer 1Part aTable 1: ANOVA tableSource of VariationSum of squaresDegrees ofFreedomMean SquareFBetween treatments903= 90/3 = 30= 30/6 = 5Within treatments (Error)12020= 120/20 = 6Total= 90 + 120= 210= 3+20=23At = 0.01, p-value = 0.0095 for F(3,20). Hence we have sufficient evidence to rejectNull Hypothesis. Part bThe number of groups = degrees of freedom (between treatment) + 1 = 3+1 = 4Part cThe number of observations = degrees of freedom (within treatment) + 1=20 +1 = 21Answer 2Table 2: Coefficients of Regression EquationCoefficientsStandard Errort StatP-valueIntercept136.000013.76319.881460.00001Year (t)39.18182.218117.664330.00000The regression equation for the trend line is: Number of Units sold (000s) = 136 + 39.1818*YearHence, number of units that can be sold in 11th year = 136+39.1818*11 = 566.9998 ≈ 567 (000s)
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