EGB360 Plant and Process Design Question and Answer 2022
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Added on 2022/10/19
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technical assignment about the pumping system design. all the assignment information is attached along with the supporting information.
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EGB360–PlantandProcessDesign Water need to be transferred from reservoir A to B and C The pump shall be between 200 to 250m downstream of reservoir A The following are the modes of operation, with parameters to be considered for design. MODE (I) (Designcondition 1) –Normalflow rate fromreservoir A to be 250 litres/second –Dischargeinto ReservoirBtobe50litres/sandinto ReservoirCtobe200litres/s. MODE (II) (Designcondition 2) –Normalflow rate fromreservoir A to be 250 litres/second –Dischargeinto ReservoirBtobe80litres/sandinto ReservoirCtobe170litres/s. MODE (III) (Allflowto ReservoirC) –Thesamenumber of pumps running as in MODE (I) –Control valve in Line D-C setto cause all flow running into Reservoir C, i.e. no water to be discharged into or drained from Reservoir B. Tasks: 1.Draw a detailed systemschematicfor MODE (I), allowing for sufficientvalves (nonon-returnvalvesinLineD-B)andatleastthree90Obendsperpipe section. 2.Show the selectedpipelinediametersandtheirassociatedheadlosses(based ongood engineering practice) inatableandjustifythereasonsforyour componentselection. For MODE (I) & (II) 3.Show the expectedpumpoperating points forMODE(I) & (II) and demonstratethese byshowing pump performance and systemresistance curves. Compare the performance of the two design conditions 4.Determinetheamountof themainsuctionisolation valve to be throttled in MODE (I)& (II) inordertomatchanNPSHsafetyfactor of 1.15 for thepumps. 5.Showpumpoperating points, systemresistancecurves and control valve settings foroperationinMODE(III). Solution We shall find the pump rating for the system, knowing the flow rate and the head The formula is Power(HP)=TDHXQXSG 3960 Where: TDH stands for the total dynamic head, the height the liquid travels including the frictional losses, Q is the flow rate in m3/s, SG is the specific gravity for water the value is 1. 3960 is a factor for horsepower conversion. We shall consider the highest reservoir
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1000X250 3960=63.13HP This is for the three pumps, we shall assume they have the same ratings, meaning the pump at the same rate. Parameters to be considered, The valves The pipe sizes The water needs to be supplied in such a way that the valves will allow 1/5 of water from A to flow to B, and 4/5 of water to flow in C. (The diagram) Question 2 Head loss Loss of energy head = difference between the levels of the two reservoirs By using the discharge rates, we shall find the diameters of the pipes Then find the velocity, by using the continuity equation Question 3