logo

Electrical Engineering Assignment

15 Pages1212 Words268 Views
   

Added on  2020-04-21

Electrical Engineering Assignment

   Added on 2020-04-21

ShareRelated Documents
Engineering Science Electrical 1A CALCULATION PAPER ON ENGINEERING SCIENCE ELECTRICAL A Calculation Paper on Circuits ByStudent’s NameName of the ProfessorInstitutional AffiliationCity/StateYear/Month/Day
Electrical Engineering Assignment_1
Engineering Science Electrical 2QUESTION 1Use Kirchhoff’s Law to find the value of currents Ix, Iy, Iz and the voltages Vp and Vq in Fig 1a and 1b:By the use of Kirchhoff’s current law which states that the total current entering a circuit junction is exactly equal to the total current leaving the same junction:6.3A + Iy + 1.7A = 3.8A8 + Iy = 3.8Iy = -4.2A5.9A + 1.7A = 2.4A + Ix7.6A = 2.4A + IxIx = 5.2A4.1A = Iz + Ix + Iy4.1 = Iz + 5.2 + -4.24.1 = Iz + 1Iz = 3.1A
Electrical Engineering Assignment_2
Engineering Science Electrical 3By the use of the Kirchhoff’s voltage law which states that the algebraic sum of all the voltages around any closed loop in a circuit is equal to zero, the figure above can be divided into two loops:[ CITATION Ros14 \l 2057 ]Loop 1Vp – 2.1V + -2.4 + 9.8V + - 5V + - 1.9V = 0Vp + 9.8V = 2.1V + 2.4V + 5V + 1.9VVp + 9.8V = 11.4VVp = 1.6VLoop 2Vq + 9.8V + 0.5V + -5V – 1.2V -2.7V = 0VVq + 9.8V + 0.5V = 5V + 1.2V + 2.7VVq + 10.3V = 8.9Vq = -1.4V
Electrical Engineering Assignment_3
Engineering Science Electrical 4QUESTION 2Using loop analysis determine the current in each resistor in fig 2When 12V supply is open circuit, then the circuit will be as shown in the figure below: For loop 1: 18V = 12I1 + 3I3When 18V supply is open circuited as shown above:12V = 6I2 + 3I3..................................................(i)But: I1 +I2 = I3.............................................. (ii)18V = 12I1 + 3I3.............................................. (iii)
Electrical Engineering Assignment_4

End of preview

Want to access all the pages? Upload your documents or become a member.