Statistical Analysis of F-35 Fighter Jet Locations: Course Name/Code
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Homework Assignment
AI Summary
This assignment presents a statistical analysis of F-35 fighter jet locations, examining the data's distribution, skewness, and the application of the Central Limit Theorem. The analysis includes the calculation of z-scores for different locations, such as Fairchild, Castle, and Beale, to determine the pro...

STATISTICS
FLYING SQUADRON F-35 FIGHTER JET
Student ID:
[Pick the date]
FLYING SQUADRON F-35 FIGHTER JET
Student ID:
[Pick the date]
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The requisite screenshot as obtained from StatDisk is shown below.
The requisite output from Excel is shown below.
The requisite output from Excel is shown below.

Question 1
Taking into consideration the histogram for the data coupled with the Q-Q plot obtained
using StatDisk, it can be said that the data did not arise from a normal population. The
reasons are explained below (Flick, 2015).
ï‚· There is significant amount of skew present in the data as the tail on the right is
significantly longer than the tail to the left of the mean. Normal distributions are
expected to be symmetric.
ï‚· The Q-Q plot (i.e. blue dots) tends to significantly deviate from the expected straight
line denoted in green.
Question 2
The data sample mean cannot be treated as a value from a normal distribution as the mean
value. This is because the mean value is highly skewed by the presence of large data values.
Also, considering that the sample size is small, hence in accordance with Central Limit
Theorem, the given sample cannot be assumed to be normal (Hillier, 2016).
Question 3
An unusually high z value score would occur for locations such as Fairchild and Castle. The
relevant computation is shown below.
Z score (Fairchild) = (23.40-6.02)/(7.47/150.5) = 9.02
Also, unusually low z value score would occur for Beale location. The relevant computation
is shown below.
Z score (Beale) = (0.60-6.02)/ (7.47/150.5) = -2.81
Question 4
The associated probabilities for Fairchild and Castle would be lower than 0.05. This is also
true for Beale. This would imply that Fairchild and Castle are pivotal bases for the national
security of the nation or may be secure than other bases owing to which such a significant
Taking into consideration the histogram for the data coupled with the Q-Q plot obtained
using StatDisk, it can be said that the data did not arise from a normal population. The
reasons are explained below (Flick, 2015).
ï‚· There is significant amount of skew present in the data as the tail on the right is
significantly longer than the tail to the left of the mean. Normal distributions are
expected to be symmetric.
ï‚· The Q-Q plot (i.e. blue dots) tends to significantly deviate from the expected straight
line denoted in green.
Question 2
The data sample mean cannot be treated as a value from a normal distribution as the mean
value. This is because the mean value is highly skewed by the presence of large data values.
Also, considering that the sample size is small, hence in accordance with Central Limit
Theorem, the given sample cannot be assumed to be normal (Hillier, 2016).
Question 3
An unusually high z value score would occur for locations such as Fairchild and Castle. The
relevant computation is shown below.
Z score (Fairchild) = (23.40-6.02)/(7.47/150.5) = 9.02
Also, unusually low z value score would occur for Beale location. The relevant computation
is shown below.
Z score (Beale) = (0.60-6.02)/ (7.47/150.5) = -2.81
Question 4
The associated probabilities for Fairchild and Castle would be lower than 0.05. This is also
true for Beale. This would imply that Fairchild and Castle are pivotal bases for the national
security of the nation or may be secure than other bases owing to which such a significant
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number of F -35 fighters are found on this base. The opposite would be true for Baele where
the number of F-35 fighters is unusually low.
Question 5
The excel computations imply that average F-35 fighters on a given location is 6.02. The
dispersion in the number of F-35 fighters across locations is quite high as the standard
deviation at 7.47 is higher than the mean. This is indicative of a large variation amongst
locations in regards to F-35 fighters. The z score corresponding to Charleston base is -0.59
which implies that number of F -35 fighter jets at this base are 0.59 times standard deviation
lower than the average F-35 jets in each location. The corresponding probability for this base
comes out as 0.2769 which implies that there is a 27.69% chance that a given base/location
would have lesser F-35 fighters than Charleston.
the number of F-35 fighters is unusually low.
Question 5
The excel computations imply that average F-35 fighters on a given location is 6.02. The
dispersion in the number of F-35 fighters across locations is quite high as the standard
deviation at 7.47 is higher than the mean. This is indicative of a large variation amongst
locations in regards to F-35 fighters. The z score corresponding to Charleston base is -0.59
which implies that number of F -35 fighter jets at this base are 0.59 times standard deviation
lower than the average F-35 jets in each location. The corresponding probability for this base
comes out as 0.2769 which implies that there is a 27.69% chance that a given base/location
would have lesser F-35 fighters than Charleston.
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References
Flick, U. (2015). Introducing research methodology: A beginner's guide to doing a research
project (4thed.). New York: Sage Publications.
Hillier, F. (2016).Introduction to Operations Research.(6thed.). New York: McGraw Hill
Publications.
Flick, U. (2015). Introducing research methodology: A beginner's guide to doing a research
project (4thed.). New York: Sage Publications.
Hillier, F. (2016).Introduction to Operations Research.(6thed.). New York: McGraw Hill
Publications.
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