For your third journal entry, consider again the variable DP05.

Added on - 16 Sep 2019

2
Pages
355
Words
228
Views
0
Downloads

Share on Facebook Share on Twitter Share on LinkedIn Share on Whatsapp Share on Mail Copy Link

Trusted by +2 million users,
1000+ happy students everyday

Showing pages 1 to 1 of 2 pages

For your third journal entry, consider again the variable DP05. How many months had no dayswith 0.5 inches or more of precipitation? What proportion of months had no days with 0.5 inchesor more of precipitation? Construct a 95% confidence interval for the proportion of months thathad no days with 0.5 inches or more of precipitation. Does this analysis make sense?SolutionThe total sample size is 347. Out of 347, 36 months had no days with 0.5 inches or more ofprecipitationThe proportion of months had no days with 0.5 inches or more of precipitation is 0.1037The 95% confidence interval for the proportion of months that had no days with 0.5 inches ormore of precipitation is calculated by using the formula given below(p−Z1−α2∗√p∗(1−p)n,p+Z1−α2∗√p∗(1−p)n)(0.1037−1.96∗√0.1037∗(1−0.1037)347,0.1037+1.96∗√0.1037∗(1−0.1037)347)= (0.0717, 0.1358)Therefore, the95% confidence interval for the proportion of months that had no days with 0.5inches or more of precipitation is(0.0717, 0.1358)Now consider the variable EMXT (extreme maximum temperature). Construct a 99% confidenceinterval for the extreme maximum temperature for a month. Does this analysis make senseThe 99% confidence interval for the extreme maximum temperature for a month is calculated byusing the formula given below(́x−t1−α2,(n−1)∗s√n,́x+t1−α2,(n−1)∗s√n)The table given below shows the workings of confidence interval of extreme maximumtemperature for the month