Frequency distribution of Melbourne 20 18 18 16 14 12 to 1577 1577 to 1859 1 1 1859 to 2140 2140 to 2422 2422 to 2703 Number of passengers at train station (Melbourne) 20 18 18 16 14 12

[Date]

Question 1
a. Frequency distribution with the help of 10 classes is shown below.
b. Histogram
282 to
451
451 to
732
732 to
1014
1014 to
1295
1295 to
1577
1577 to
1859
1859 to
2140
2140 to
2422
2422 to
2703
2703 to
2985
0
2
4
6
8
10
12
14
16
18
20
18
12
8 8
3
5
1 1 1
3
Histogram
Number of passengers at train station in Melbourne
Number of passengers at train station (Melbourne)
Frequency
c. Mean, Median and mode of the data set is computed as highlighted below.
Sorted data: Ascending order
1

2

Mean The average of the data set would be sum of data values divided by
sample size.
Median Median
Mode Highest frequency has been observed for the data value 401 and thus,
the mode will be 401.
Question 2
a. The decision about recognition of provided data being sample or population is mainly
dependent on whether the data is part of some other large data set or the whole population
itself. In present case, the data is given only for the seven weeks not for the whole time
for which Holmes was opened and hence, it can be said that the data set is taken from a
large population and thus, would be considered as sample not population.
b. Computation of standard deviation
Variable of interest: Weekly attendance of student in Holmes
Mean ¿
¿ 1
n ∑ x
¿(472+413+ 503+612+399+538+ 455)/7=484.57
Standard deviation
3