Genetic Diversity - Study Material with Solved Assignments

Running head: GENETIC DIVERSITY
GENETIC DIVERSITY
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GENETIC DIVERSITY
1
Answer no 1.
A) The study of how gene interact to produce a phenotype
Answer no 2.
True
Answer no 3.
As rose combed chicken is dominant to single combed chicken,
Allele of Rose combed chicken – RR (homozygous dominant)
Allele of single-combed chicken- rr (homozygous recessive)
When homozygous rose combed chicken (RR) mated with the single combed hen (rr), all the
chicken in the F1 generation will be heterozygous rose combed.
Homozygous rose combed chicken
R R
Recessive single
combed Hen
r Rr Rr
r Rr Rr
Therefore, in F1 generation, all the chicken have Rr gametes and are heterozygous rose combed
chicken.

GENETIC DIVERSITY
2
In F2, there is self-mating of Rr × Rr
Heterozygous rose combed chicken
R r
Heterozygous rose
combed Hen
R RR
(rose combed)
Rr
rose combed
r Rr
(rose combed)
rr
(single-combed)
A) The genotypic ratio of F2 generation is 1(RR) :2 (Rr):1 (rr)
B) The phenotypic ratio of F2 generation is 3 (red combed) : 1 (single-combed)
Answer no 4.
Allele of heterozygous man for blood type A – IA Io
Allele of Woman heterozygous for blood type B- IB Io
IA Io × IB Io
In order to have type O blood group, both of the parents must carry a recessive allele.