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HI6007 Assignment on Statistics

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Added on  2020-05-16

HI6007 Assignment on Statistics

   Added on 2020-05-16

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Running Head: HI6007 STATISTICS ASSIGNMENTHI6007 Statistics AssignmentName of the StudentName of the UniversityAuthor Note
HI6007 Assignment on Statistics_1
HI6007 STATISTICS ASSIGNMENT1Table of ContentsAnswer 1..........................................................................................................................................2Answer 2..........................................................................................................................................2Answer 3..........................................................................................................................................3Answer 4..........................................................................................................................................4Answer 5..........................................................................................................................................4Answer 6..........................................................................................................................................5Answer 7..........................................................................................................................................5Answer 8..........................................................................................................................................7Answer 9..........................................................................................................................................7Answer 10........................................................................................................................................8
HI6007 Assignment on Statistics_2
HI6007 STATISTICS ASSIGNMENT2Answer 1(a)Source of VariationSum ofSquaresDegrees ofFreedomMean SquareFBetween treatmentsSSB =90(k – 1) = 3MSB = (SSB / k– 1) = 30(MSB / MSE) =5Within treatments (Errors)SSE =120(N – k) = 20MSE = (SSE / N– k) = 6TotalTSS =210(N – 1) = 23The critical value of F at α = 0.01 with 3 and 20 degrees of freedom is 4.94. Thecalculated value of F is higher than the significance value. Thus, there is significantdifference between the means. (b)The number of groups is k. Therefore, the number of groups in this problem is 4(c)The total number of observations is N. Therefore, the number of observations in thisproblem is 24.Answer 2The projection equation can be estimated with the help of regression analysis. The results of theregression analysis as obtained from the excel is given in the following table: CoefficientsStandard Errort StatP-valueIntercept13613.7639.8810.000Year (t)39.182.21817.6640.000The linear trend expression to project the sales is given by: T = 136 + 39.18 * tThe projected sales for t = 11 is 136 + (39.18 * 11) = 567
HI6007 Assignment on Statistics_3

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