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HIGHER COLLEGE OF TECHNOLOGY DEPARTMENT OF ENGINEERING Section.

   

Added on  2022-08-01

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Part A (2x2.5 = 5 Marks)
1. Solve the partial differential equation2
2
2
2
6 t
z
x
z




 [2.5]
Solution: The characteristic equation is2 6 6m m i    . Then by using D’Alembert method,
the general solution is

, 6 6z x t f x i t g x i t
HIGHER COLLEGE OF TECHNOLOGY
DEPARTMENT OF ENGINEERING
Section Electrical & Electronics Engineering
Student Name
I.D. Number
Quiz II-ASSIGNMENT Semester-II AY 2019 - 20
Max.
Marks:
10 Course Name: Engineering Mathematics
Level: A.DIPLOM
A
Course Code: MATH3120N
Section No. Specialization Common
Date Of
Submission
:
Lecturer’s/Course
Coordinator Name:
Dr.Ganesh Venkataraman

2. Find
ttL 22 cos . [2.5]
Solution: We know that2 cos 2 1
cos 2
t
t
. So

 
2
2 2
cos 2 1
cos 2
1 cos 2 1
2
1 cos 2 1
2
1 1
2 2
t
L t L
L t
L t L
s
s s







We know that 

 


1
n
nn
n
d
L t f t L f t
ds
  , so





2
22 2 2
2
2
6 2
33 2
2 2 2
cos 1 cos
1 1
2 2
2 24 32
4
d
L t t L t
ds
d s
d
s s
s
s s
s
s









Hence,

6 2
33
2
2
2 2 2 3
4
c 2
s 4
oL s s
s s
t t

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