Running head: COMMUNICATION SYSTEM1Communication SystemsNameInstitution
COMMUNICATION SYSTEMS2CDMAQuestion 1To test whether the spreading codes are orthogonal, we apply the dot product.U1U2=[−11−111]∗[−1−11−1−1]=−3U2U3=[−1−11−1−1]∗[1−111−1]=1U1U3=[−11−111]∗[1−111−1]=−3Therefore, the spreading codes are not orthogonal.Question 2User U1=[−11−111]Bit sequence b=[b0,b1]=¿ [1 1] The transmitted symbols will be=[~b,b,~b,b,b]=¿=[0,0,1,1,0,0,1,1,1,1]User U2=[−1−11−1−1]Bit sequence b=[b0,b1]=¿ [1 1]The transmitted symbols will be=[~b,~b,b,~b,,~b]=[0,0,0,0,1,1,0,0,0,0]User U3=[1−111−1]Bit sequence b=[b0,b1]=¿ [1 -1]The transmitted symbols will be=¿
COMMUNICATION SYSTEMS3Question 3The received signal ignoring noise is the same as the transmitted signal which will be [0,0,1,1,0,0,1,1,1,1] for user U1[0,0,0,0,1,1,0,0,0,0] for user U2[1,−1,0,−1,1,−1,1,−1,0,−1] for user U3Question 4Despread signals for the three users are computed as follows:User U1=[−11−111], Despread signal for user U1=[1,0,1,0,0]User U2=[−1−11−1−1] Despread signal for user U2=[1,1,0,1,1]User U3=[1−111−1] Despread signal for user U3=[0,1,0,0,1]Question 5The number of users,N=1+WREbIo=1+1286=22.3333≅23 usersQuestion 6Each subscriber generates 2 calls/day¿10×2mindayThe traffic load is ¿10×2×6024×3600=172=0.013888889Erlangssubscriber
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