IP Addressing Solution for uSoft Software Company

Verified

Added on  2024/05/27

|7
|983
|429
AI Summary

Contribute Materials

Your contribution can guide someone’s learning journey. Share your documents today.
Document Page
4/22/2018
ASSIGNMENT-2
DATA COMMUNICATONS AND NETWORKS
John Cena
Microsoft

Secure Best Marks with AI Grader

Need help grading? Try our AI Grader for instant feedback on your assignments.
Document Page
Contents
Introduction.................................................................................................................................................2
Network connectivity Diagram....................................................................................................................2
Host Machine..............................................................................................................................................2
IP Addressing...............................................................................................................................................3
IPv4 Address............................................................................................................................................3
IPv6 Address............................................................................................................................................5
Conclusion...................................................................................................................................................6
Document Page
Introduction
The main purpose of this report is to provide the IPv4 and IPv6 address solution to the uSoft Software
company. The software solution provided by the company has a data center and need the subnetting
solution which can support their requirement. The company has one head quarter and two branch
offices spread over the Gold Coast region.
Network connectivity Diagram
The three offices of the uSoft company is connected using the Internet. And all the branches are
connected to the internet using the edge router. And the MPLS protocol provides the internet network
connectivity of all the offices.
Given below network diagram shows the basic connectivity of the offices.
Fig : Network connectivity Diagram of all the offices
Host Machine
Now according to the given company device information. The number of devices present in all the
offices are given below.
- Head Quarter : 100
- Branch A : 30
- Branch B : 20
Document Page
IP Addressing
The IP addressing is the most important part of the network connectivity. So the company has taken the
new address space. So the IP address need to be redesigned for the whole network. So the proposed IP
addressing solution for the company is given below for both IPv4 and IPv6.
IPv4 Address
The company has been allotted with the following IPv4 Subnet
203.2.2.0/24
So the addresses require by different branches are given below one by one.
Head Quarter
No. of address required for devices = 100
So the address number of bits required in the host bit to full fill this required is 7.
Now subnet address = 203.2.2.0/25
Subnet Mask = 255.255.255.128
Network ID = 203.2.2.0
Broadcast Address = 203.2.2.127
Address range = 2^n-2
= 2^7-2
= 128 – 2
= 126
So the useful address range = 203.2.2.1- 203.2.2.126
Default Gateway for this network = 203.2.2.1
Free Addresses = 126 – 100 = 26
Key Address
Router Interface = 203.2.2.125
Server Addresses = 203.2.2.120 – 124
Printer Address = 203.2.2.119 – 120
Branch A
No. of address required for devices = 30
So the address number of bits required in the host bit to full fill this required is 5.
Now subnet address = 203.2.2.128/27

Secure Best Marks with AI Grader

Need help grading? Try our AI Grader for instant feedback on your assignments.
Document Page
Subnet Mask = 255.255.255.224
Network ID = 203.2.2.128
Broadcast Address = 203.2.2.158
Address range = 2^n-2
= 2^5-2
= 32 – 2
= 30
So the useful address range = 203.2.2.129- 203.2.2.157
Default Gateway for this network = 203.2.2.129
Free Addresses = 30 - 30 = 0
Key Address
Router Interface = 203.2.2.129
Server Addresses = 203.2.2.156
Printer Address = 203.2.2.157
Branch A
No. of address required for devices = 20
So the address number of bits required in the host bit to full fill this required is 5.
Now subnet address = 203.2.2.160/27
Subnet Mask = 255.255.255.224
Network ID = 203.2.2.160
Broadcast Address = 203.2.2.191
Address range = 2^n-2
= 2^5-2
= 32 – 2
= 30
So the useful address range = 203.2.2.161- 203.2.2.190
Default Gateway for this network = 203.2.2.161
Free Addresses = 30 - 20 = 10
Key Address
Document Page
Router Interface = 203.2.2.161
Server Addresses = 203.2.2.189
Printer Address = 203.2.2.190
IPv6 Address
For the IPv6 address the company has been allocated with the following subnet
2001:1234:ABCD:0200::/64
The addressing solutions are always done using the requirement of the host in the network. Now the
IPv6 works similarly to the IPv4 but the number of addresses provided by the IPv6 are very large. Now
the number address required for different branches are not too much so we can fulfill the requirement
of the address in a very small subnet. So the solution are given below.
Head Quarter
The number of host machine required = 100
Number of bits required = 7
So the subnet address = 2001:1234:ABCD:0200::/121
Expanded address = 2001:1234:ABCD:0200:0000:0000:0000:0000/121
Prefix = FFFF:FFFF:FFFF:FFFF:FFFF:FFFF:FFFF:FF80
Range = 2001:1234:ABCD:200:0:0:0:0 - 2001:1234:ABCD:200:0:0:0:7F
Number of free address = 26
Default Gateway = 2001:1234:ABCD:0200::1
Key Address
Server Address = 2001:1234:ABCD:0200::2
Printer Address = 2001:1234:ABCD:0200::3
Branch A
The number of host machine required = 30
Number of bits required = 5
So the subnet address = 2001:1234:ABCD:0200::128/123
Expanded address = 2001:1234:ABCD:0200:0000:0000:0000:0128/123
Prefix = FFFF:FFFF:FFFF:FFFF:FFFF:FFFF:FFFF:FFE0
Range = 2001:1234:ABCD:200:0:0:0:120 - 2001:1234:ABCD:200:0:0:0:13F
Document Page
Number of free address = 0
Default Gateway = 2001:1234:ABCD:0200::129
Key Address
Server Address = 2001:1234:ABCD:0200::130
Printer Address = 2001:1234:ABCD:0200::131
Branch B
The number of host machine required = 20
Number of bits required = 5
So the subnet address = 2001:1234:ABCD:0200::160/123
Expanded address = 2001:1234:ABCD:0200:0000:0000:0000:0160/123
Prefix = FFFF:FFFF:FFFF:FFFF:FFFF:FFFF:FFFF:FFE0
Range = 2001:1234:ABCD:200:0:0:0:160 - 2001:1234:ABCD:200:0:0:0:17F
Number of free address = 10
Default Gateway = 2001:1234:ABCD:0200::161
Key Address
Server Address = 2001:1234:ABCD:0200::162
Printer Address = 2001:1234:ABCD:0200::163
Conclusion
Now according to the proposed IPv4 and IPv6 networking addressing solution will help in providing the
connectivity as required by the uSoft company. If there is demand in the future upgrade then we just
need to use the free subnet to the existing network.
1 out of 7
circle_padding
hide_on_mobile
zoom_out_icon
[object Object]

Your All-in-One AI-Powered Toolkit for Academic Success.

Available 24*7 on WhatsApp / Email

[object Object]