ITC212 Answer to Question 1: Ethernet/IP/TCP Combination Can accommodate 1492 - TCP Header - IP header + Ethernet Trailer = 1492 - 24 -24 = 1444

Running head: ITC212
ITC212
Name of the Student
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Author’s Note

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ITC212
Answer to Question 1:
Ethernet/IP/TCP combination can accommodate 1492 – TCP Header – IP header – (Ethernet
header + Ethernet Trailer)
= 1492 – 24 -24
=1444
Thus 1 frame would be needed for transmitting the data packet
TCP (Total Overhead is 24 bytes)
1 Source_ID 16 bits
2 Destination_ID 16 bits
3 Sequence_number 32 bits
4 ACK number 32 bits
5 Header _length 4 bits
6 Unused 6 bits
7 Flags 6 bits
8 Flow control 16 bits
9 CRC 16 16 bits
10 Urgent pointer 16 bits
11 Options 32 bits
Total 192 bits or 24 bytes
IP (Total Overhead is 24 bytes)

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1 Version number 4 bits
2 Header length 4 bits
3 Type of Service 8 bits
4 Total length 16 bits
5 Identifiers 16 bits
6 Flags 3 bits
7 Packet offset 13 bits
8 Hop limit 8 bits
9 Protocol 8 bits
10 CRC 16 16 bits
11 Source address 32 bits
12 Destination Address 32 bits
13 Options 32 bits
Total 192 bits (24 bytes)
Ethernet Total overhead = 33 bytes
Overhead
33 + 24 + 24 = 81
1200
Efficiency (%) = ----------------------------------------------- *100% = 93.67%
1200 + 81

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Answer to Question 2:
2.1. Consider an IP subnet with prefix 170.16.10.198/26. Provide the range of IP addresses
Assignable Range - 170.16.10.193 to 170.16.10.254
2.2. Block of IP address = 170.16.10.198/26
Prefixes for the four IP subnet are given below:
Subnet 1:
170.16.10.192 /28
Subnet 2:
170.16.10.208 /28
Subnet 3:
170.16.10.224 /28
Subnet 4:
170.16.10.240 /28

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Bibliography
Edwards, J., & Bramante, R. (2015). Networking self-teaching guide: OSI, TCP/IP, LANs,
MANs, WANs, implementation, management, and maintenance. John Wiley & Sons.
Syed, Z. A. (2017). Internetworking Layer.