Comparison of Iteration and Recursion in C#

This article compares the implementation of iteration and recursion in C# with examples and test results. It includes code snippets for both methods and explains the differences between them. The test results for each method are also provided with sample inputs. The subject is computer programming, and the course code is B7IT127. The article is relevant for students studying computer science or programming courses in any college or university.

Assessment 1
Iteration Code:
using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;
using System.Threading.Tasks;
namespace B7IT127Ass1
{
class Program
{
static void Main(string[] args)
{
Int32 n, x, d,i,sum; //variable declaration
try
{
Console.Write("Enter the value of n : "); //get the value
of n, x and d from keyboard
n = Int32.Parse(Console.ReadLine());
Console.Write("\nEnter the value of x : ");
x = Int32.Parse(Console.ReadLine());
Console.Write("\nEnter the value of d : ");
d = Int32.Parse(Console.ReadLine());
Console.WriteLine();
for(i=1; i<=n;i++) //loop starts
{
sum=x+ d * (i-1); //find the value
of sum (series of number)
Console.WriteLine("A("+i+") = "+sum ); //print the
result
}
Console.WriteLine();
Console.ReadKey(); //wait for user press any key
to exit
}
catch(FormatException fex) //if any input data type
error found, it catches and print the error message
{
Console.WriteLine("Error : " + fex.Message);
}
catch (Exception ex) //if any error found in the process
or input, it catches and print the error message
{
Console.WriteLine("Error : " + ex.Message);
}
}
}
}

Test Results:
If n = 6, x = 3 and d = 4
Explanation:
If n = 6, x = 3 and d = 4
Iteration i Iterative
Condition (i < n)
Sum or A(i)
1 1 1 < 6 (true) 3 + 4 (1-1)=3
2 2 2 < 6 (true) 3 + 4 (2-1)=7
3 3 3 < 6 (true) 3 + 4 (3-1)=11
4 4 4 < 6 (true) 3 + 4 (4-1)=15
5 5 5 < 6 (true) 3 + 4 (5-1)=19
6 6 6 < 6 (true) 3 + 4 (6-1)=23
7 7 7 < 6 (false), loop
ends

Recursion Code:
using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;
using System.Threading.Tasks;
namespace B7IT127Ass1Recur
{
class Program
{
static void Main(string[] args)
{
Int32 n, x, d; //variable declaration
try
{
Console.Write("Enter the value of n : "); //get the value
of n, x and d from keyboard
n = Int32.Parse(Console.ReadLine());
Console.Write("\nEnter the value of x : ");
x = Int32.Parse(Console.ReadLine());
Console.Write("\nEnter the value of d : ");
d = Int32.Parse(Console.ReadLine());
Console.WriteLine();
recurSequence(n, x, d, 1); //call the recursion function
Console.WriteLine();
Console.ReadKey(); //wait for user press any key
to exit
}
catch (FormatException fex) //if any input data type
error found, it catches and print the error message
{
Console.WriteLine("Error : " + fex.Message);
}
catch (Exception ex) //if any error found in the process
or input, it catches and print the error message
{
Console.WriteLine("Error : " + ex.Message);
}
}
public static void recurSequence(int n, int x, int d,int i)
//recursion function starts
{
int sum;
if((n-i)<0) //if the series exceed the stop value,
exit from the recursion
{
return ;
}
sum = x + d * (i - 1); //find the value
of sum (series of number)
Console.WriteLine("A(" + i + ") = " + sum); //print the
result
recurSequence(n, x, d,++i);
}
}

}
Test Results:
If n = 5, x = 6 and d = 3
Explanation:
If n = 5, x = 6 and d = 3
Iteration Recursion function
(recurSequence(n,x,d,i)
i Iterative Condition ((n-i) <0) Sum or A (i)
1 recurSequence(5,6,3,1) 1 1 < 6 (true) 6 + 3 (1-1)=6
2 recurSequence(5,6,3,2) 2 2 < 6 (true) 6 + 3 (2-1)=9
3 recurSequence(5,6,3,3) 3 3 < 6 (true) 6 + 3 (3-1)=12
4 recurSequence(5,6,3,4) 4 4 < 6 (true) 6 + 3 (4-1)=15
5 recurSequence(5,6,3,5) 5 5 < 6 (true) 6 + 3 (5-1)=18
6 recurSequence(5,6,3,6) 6 6 < 5 (false), loop ends