# Math 243 Group Project - Probability Distribution, Mean, Standard Deviation, Binomial Distribution, Sample Proportion

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MATH 243 GROUP PROJECT
[DATE]
Problem 1
Probability distribution
(a) Mean μ= xP(x )= ( 02 % )+ ( 18 % )+ ( 239 % ) + ( 335 % ) + ( 416 % )=2.55
Variance σ 2= x2P(x )μ2=7.35 ( 2.55 ) 2=0.8475
Standard Deviation = sqrt (Variance) = 0.8475=0.9206
(b) Percentage probability of getting 3 or better = 35% +16% = 51%
Percentage probability of getting 2.5 or better = 35% +16% = 51%
Problem 2
(a) Let a is the missing entry
Further,
a= 60045 %
55 % =491
Hence, the missing entry would be 491.
(a) The complete table
μx= xP(x )
μx= ( 6000.55 ) + ( 4910.45 )
μx=550.95
Hence, the complete table is shown below.
X units 600 491
1
Probability 55% 45%
Problem 3
A fair coin has tossed 6 times which indicates that possible outcomes would be 2^6 = 64
Let x is the variable which has highest count of heads in row occurring in 6 tosses.
(a) Probability distribution table
(b) The value of μxσ x
The value of μx
The value of σ x
Now,
σ x= 1.5=1.2247
Problem 4
(a) Mean and standard deviation of sample heads of count x for 250 tosses
2

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