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Mathematics Determinants-Assignment

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Added on  2021-04-24

Mathematics Determinants-Assignment

   Added on 2021-04-24

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Q1a2−2−1212435xyz = 112B Getting 1 at the right hand connerR1/2 = r1= (1 -1 -1/2 1/2)1−1−1/22124351/212Getting 0 on second row first column-2r1+r2 =r2(-2,2,1,-1)+(2,1,2,2)=(0,3,3,0)1−1−1/20334351/202Getting 0 on third row first column-4r1+r3 =r3(-4,4,2,-2)+(4,3,5,2)=(0,7,,0)1−1−1/20330771/200Getting 1 on second row second columnR3/31−1−1/20110771/200Getting 0 on third row second column-7r2+r3 =r3
Mathematics Determinants-Assignment_1
(0,-7,-7,0)+(0,7,7,0 =(0,0,1,1)1−1−1/20110001/200Getting 1 on third row third columnr3 +1=r31−1−1/20110011/201Getting 0 on second row third column-r3 +r2=r21−1−1/20100011/2−11Getting 0 on first row third column1/2r3 +r1=r11−100100011−11Getting 0 on first row second columnR2 +r1=r11000100010−11Therefore x=0, y=-1 and z=1c. Determinant of matrix A2−2−1212435 = 2{(5*1-3*2) –2{(2*5-2*4)}+-1{2*3-4*1}Determinant = -2
Mathematics Determinants-Assignment_2
d. the determinant is above is useful in finding the inverse of the matrix.e. c(3c-5)+2(4c-10)+1(-2)3c2-5c+8c-20—2=03c2 +3c-22=0C= -3.25 or 2.25Q2a.112212435xyz = 212b.Determinant = -1+-2+4 = +1We have 1 at the upper coner, R1/2 = r1= (1 -1 -1/2 1/2)112212435212Getting 0 on second row first column-4r1+r2 =r21120−1−24352−32Getting 0 on third row first column-4r1+r3 =r31120−1−20−1−32−3−6
Mathematics Determinants-Assignment_3

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