Maths Project with Solved Questions and Answers

This Maths project covers solved questions and answers on topics like significant figures, linear equations, and more. It is perfect for students of all levels and provides a comprehensive understanding of the subject matter. The project includes solutions to questions on topics like algebra, geometry, and trigonometry.

Maths Project

Question 1
(F)
The three significant figures,
= 1.496 *1011 /3 *108
= 498.66 seconds
= 998.66 /60
= 8.311mins.
= 8.311/60
= 0.13851 hours.
No, danesh was not corrected about the answer. 1011 * 109 = 1020. While danesh multiplied the
power, he should added those values.
Question 2
(A)
3/5*240
= 144
=5/100*240
=36
240-144-36-12
= 48
(B)
200* 103.3 *101.5 = 209.7
First year = 3.3 percent
Second year = 1.5 percent
Question 3
(A)
while this have been given that,
2 pens each with black
5 pens each with red
6 pens each with green pens
1

and total number of 122 pens were sold.
so, the total number of green pens which have been sold =96
(B)
=9:4:5:2
=20:45:36:90
(C)
Ben has 20 packets,
total weight is 32 kg
32*20= 640
Lago has 25 packets,
total weight = 640/25
= 25.6
(D)
here, given that
4 bakers* 72 cakes =6*x
X=48
Question 4
(A)
p2=x-y /xy
y=8.5*109
y=4*108
= 10^8(85-4)/34*10^17
=1.54*10^-5
(B)
a) = 2*a +2*t = 5*t +7
=2*a = 3*t +7
=t = 2a -7/3
b) x = √7y +9/ y -1
(C)
i. (3x+2) (2x-1)
= 2𝑥(3𝑥+2)−1(3𝑥+2)
2

= 2𝑥(3𝑥+2)−1(3𝑥+2)
= 6𝑥2+4𝑥−3𝑥−2
= 6𝑥2+𝑥−2
ii. x2+3x - 4 /2x2 - 5x +3
= (x-1) (x+4)/ (2x+1)(x+3)
4 (D)
I. while in given linear equation in X & Y has infinite number of solution
= put x=2
= 3x-2y =7
= 3*2 -2y =7
=6 -2y =7
= 2y =6-7
= 2y -1
= y = -1/2
so the value can be, X = 2, Y= -1/2
II. h+7 /3 +2h -1/2 =5/6
= ℎ+7/3+2ℎ−1/2=5/6
= ℎ+11/6+2ℎ=5/6
= h=-1/3
4(e)
a) x2 +2x -35=0
= x² + (7 - 5)x - 35 = 0
=> x² + 7x - 5x + 35 = 0
=> x (x + 7) - 5 (x - 7) = 0
=> (x - 5) (x + 7) = 0
Therefore, Either (x - 5) = 0 or, (x + 7) = 0
=> x = 5 or, x => -7
b) 6x2-x-15=0
=2x-3=0
=3x+5=0
3

=2x=3
= 3x=-5
=x=3/2
= x=-5/3
c) 5x2+6x-2=0
5x2-6x-2/5= 0/5
= 5x2/5 -6x /5 -2/5=0
we know that,
(a-b)2=a2-2ab+b2
= -2ab = -6x /5
= -2b =-6/5
= b= 3/5
now, in given equation
x2-6x/5-2/5=0
= x2-6x/5+(3/5)2-2/5-(3/5)2=0
= (x-3/5)2= (3/5)2+2/5
= (x-3/5)2 =9/25+2/5
=(x-3/5)2 =19/25
= - 3 + √19/5 , -3 - √ 19/5
4