Mechanical System

Running head: MECHANICAL SYSTEM
MECHANICAL SYSTEM
Name of Student
Institution Affiliation

MECHANICAL SYSTEM
2
P3
Part a
Stress = Force
Area
Area= π r2
Area= 3.142*0.015*0.015
Area=0.00070695 m2
Stress = 15000
0.00070695
Stress = 21.217907Mpa

MECHANICAL SYSTEM
3
Part b
Strain ε = σ
E . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 1
Where E is the young ́s modulus, σ is the stress and ε is the strain
,ε = 21.217907
210 ×109
ε= 1.01037×10-4
Part c
ε= dl
lo . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 2
dl is the change in length, lo is the original length
dl= 5.0585×1 0−5
part d
Shear stress