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Model/Science Management

The Final Exam for MSC 3371 Spring 2018 at UIW is worth 250 points and consists of 5 questions on Linear Programming and its Applications.

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Added on  2023-06-13

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This article discusses linear programming, shadow price, and optimal solutions related to Model/Science Management. It provides answers to questions related to the optimal selling units of different models, the impact of changing the availability of ingredients, and the optimal schedule for a team of consultants. The article also mentions the availability of solved assignments, essays, dissertations, and study material for various courses and universities on Desklib.

Model/Science Management

The Final Exam for MSC 3371 Spring 2018 at UIW is worth 250 points and consists of 5 questions on Linear Programming and its Applications.

   Added on 2023-06-13

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Running head: MODEL/SCIENCE MANAGEMENT
Model/Science Management
Name of the Student:
Name of the University:
Author’s Note:
Model/Science Management_1
1MODEL/SCIENCE MANAGEMENT
Table of Contents
Answer to Question 1:.....................................................................................................................2
Requirement a:.............................................................................................................................2
Requirement b:.............................................................................................................................2
Requirement c:.............................................................................................................................3
Requirement d:.............................................................................................................................5
Requirement e:.............................................................................................................................6
Answer to Question 2:.....................................................................................................................7
Requirement a:.............................................................................................................................7
Requirement b:.............................................................................................................................8
Answer to Question 3:.....................................................................................................................8
Requirement a:.............................................................................................................................8
Requirement b:.............................................................................................................................9
Answer to Question 4:...................................................................................................................11
Requirement a:...........................................................................................................................11
Requirement b:...........................................................................................................................11
Answer to Requirement 5:.............................................................................................................13
Bibliography:.................................................................................................................................15
Model/Science Management_2
2MODEL/SCIENCE MANAGEMENT
Answer to Question 1:
Requirement a:
The optimal solution and total profit contribution is shown below:
Particulars Model A Model Z TOTAL
Selling Units 200 1040 1240
Profit Contribution per Unit $180 $250
Total Profit Contribution $36,000 $2,60,000 $2,96,000
Steel Alloy Required per unit 15 20
Total Requirement of Steel Alloy 3000 20800 23800
Manufacturing Time per unit (in minutes) 30 45
Total Manufacturing Time (in hours) 100 780 880
Assembly Time per unit (in minutes) 80 100
Total Assembly Time (in hours) 267 1733 2000
Requirement b:
If Kitto would accept the offer of the new supplier, then the new liner program would be
as follows:
Max 180A + 250Z
s.t.
15A + 20Z 35,200 Steel available
30A + 45Z 1500*60 Manufacturing minutes
80A + 100Z 2000*60 Assembly minutes
1A 200 Model A minimum frames required.
A, Z ≥ 0 Non-negativity constraints
Model/Science Management_3
3MODEL/SCIENCE MANAGEMENT
The optimal solution for this new program is given below:
Particulars Model A Model Z TOTAL
Selling Units 200 1040 1240
Profit Contribution per Unit $180 $250
Total Profit Contribution $36,000 $2,60,000 $2,96,000
Steel Alloy Required per unit 15 20
Total Requirement of Steel Alloy 3000 20800 23800
Manufacturing Time per unit (in minutes) 30 45
Total Manufacturing Time (in hours) 100 780 880
Assembly Time per unit (in minutes) 80 100
Total Assembly Time (in hours) 267 1733 2000
From the above table, it is visible that the optimal selling units of both the models would
not change even for increasing the availability of steel alloys and the total steel alloy
consumption would be under 35000 pounds. Hence, the company should not accept the offer.
Requirement c:
The new linear program and the optimal solution for the stated scenario are given below:
Max 180A + 250Z
s.t.
15A + 20Z 35,000 Steel available
30A + 45Z 1500*60 Manufacturing minutes
80A + 100Z 2500*60 Assembly minutes
1A 200 Model A minimum frames required.
A, Z ≥ 0 Non-negativity constraints
Model/Science Management_4

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