Solution 1Given:a)This is Common Emitter / Common Collector cascade type of the amplifier and feedback in this case is series feedback. The topology used is Current shunt-mixing (shunt-series) topology.Now if we do the suggested change then we have shunt-shunt topology.b)DC Voltage
SoI1=10−0.40.5k=19.2mAI1=10−0.40.64k=15mAV1=0.3VV2=0.14∗15VV2=2.1Vc)Now we can have below configurations
Considering short circuits for BJT
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