Numeracy 2 (MAII3007) Re-sit Portfolio

NUMERACY 2 (MAII3007) Re-sit Portfolio
Assignment
Student Name and id
[Pick the date]
Section 1

Question 1
a) The two laws of indices are highlighted below:
1. Any number rather than zero whose index is zero would always be equal to 1, irrespective of
the value of the base.
a0=1
1000 =1
2. When two or more expressions with the same base are taken to do multiplication than the
solution of this would be the sum of indices of the base.
am × an =am +n
52 ×53=52+3=3125
b) 35 ×33
¿ ( 3 )5 +3
¿ 38
¿ 6561
c) (10¿¿ 3)2 ¿
¿(10)3 × 2
¿(10)6
¿ 1,000,000
d) 185 ×184
¿ 18 ( 5+4 )
¿ 189
1

¿ 1.983 ×1011
Question 2
a) The requisite examples are as indicated below.
√2 = 21/2
√8 = 23/2
b) 3
√729
¿(729)
1
3
¿(9∗9∗9)
1
3
¿((9)¿¿ 3)
1
3 ¿
¿ 91
¿ 9
c) Scientific notation
Number = 9,876,567
Scientific notation = 9.876567 × 106
SKILLS AUDIT: WEEKS 1 – 2 (Taught in week 3)
I know how to.... I can do
well
I need
practice
I’m not
sure
I can’t do
1. I understand what a power of a number is. ☒ ☐ ☐ ☐
2. I can perform calculations and
simplifications using indices or powers.
☒ ☐ ☐ ☐
2

3. I understand what a root of a number is. ☐ ☒ ☐ ☐
4. I can perform calculations and
simplifications using roots and using a
scientific with a calculator.
☒ ☐ ☐ ☐
Question 3
P=£ 120,000
i=4.5 % p . a .
n=5 year
a) By simple interest
I =P∗i∗n
I = 120,000∗4.5
100 ∗5
I =£ 27,000
Total final amount at the end of 5 year A = I +P =£ 120,000+ £ 27,000=£ 147,000
b) By interest compounded annually
A=P ( 1+r )n
A=120,000∗ (1+ 0.045 )(5)
A=£ 149,541.8
c) By interest compounded semi-annually
A=P (1+ r
n )nt
A=120,000∗( 1+ 0.045
2 )
(5∗2)
3