This report focuses on the importance of numerical and data analysis in decision making. It includes arranging data in tabular and graphical form, computation of mean, mode, median, range, and standard deviation. Additionally, it presents a forecasting model for linear equations.
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NUMERACY AND DATA ANALYSIS
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TABLE OF CONTENTS INTRODUCTION.......................................................................................................................................3 MAIN BODY..............................................................................................................................................3 1.Arranging data regarding transportation expenditure in tabular form:.............................................3 2.Graphical representation of selected expenditure data.....................................................................3 3.Representing the required computation as follows..........................................................................4 4.Forecasting model for linear equation is presented as below:..........................................................8 CONCLUSION.........................................................................................................................................10 REFERENCES..........................................................................................................................................11
INTRODUCTION Data analysis is the procedure of inspecting, cleansing, transforming and modeling statistical data with the objective of utilizing information for having appropriate decision making. The present report is based on evaluating crucial data in organized manner to obtain sufficientinformationforgettingcompetitivebenefits.Thecurrentstudywillinclude presentation of data in both graphical & tabular form for transportation expenses. It will include computation of mean, mode, median, range, standard deviation.Discussion regarding linear forecasting model will be comprised in present report. MAIN BODY 1.Arranging data regarding transportation expenditure in tabular form: S. No.Month s Moneyincurredon transportation expenses 1Jan11 2Feb12 3Mar5 4April45 5May11 6June42 7July34 8Aug11 9Sept23 10Oct27 2.Graphical representation ofselected expenditure data
Jan Feb Mar April May June July Aug Sept Oct 12345678910 0 5 10 15 20 25 30 35 40 45 Money incurred on transportation expenses Money incurred on transportation expenses Jan Feb Mar April May June July Aug Sept Oct 12345678910 0 5 10 15 20 25 30 35 40 45 50 Money incurred on transportation expenses Money incurred on transportation expenses 3.Representing therequired computation as follows I.Computation of mean: S. No.Month s Moneyincurredon transportation expenses 1Jan11
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2Feb12 3Mar5 4April45 5May11 6June42 7July34 8Aug11 9Sept23 10Oct27 Totalamountofmoney spent on transportation cost221 Totalnumberof observation 10 Mean22.1 Discussion of mean value: By observing the above table it can be stated that mean value has been commutated by dividing the total amount spend with number of observation (Gill, Murray and Wright, 2021). From the calculation the mean value of selected expenditure is 22.1. II.Calculation of Median value To get the value of media two steps will be followed in sequence manner to get reliable and relevant figure. The step one is associated with arranging data set in ascending order and then second stem is applying required formula to reach conclusion. Step 1: Setting data in ascending order S. No.Month s Moneyincurredon transportation expenses
1Mar5 2Jan11 3May11 4Aug11 5Feb12 6Sept23 7Oct27 8July34 9June42 10April45 Step 2: Executing formula Median (M)Number of observations10 M(10+1)/25.5 (12+23)/217.5 Discussion of median value: From the evaluation it can articulated that the median for the specific chosen expenses is average of 5thand 6thcell. The outcome is 17.5 which has been obtained by applying mentioned formula (Deuflhard and Hohmann, 2021). III.Determination of mode value MonthsMoney incurred on transportation expenses Jan11 Feb12 Mar5 April45 May11
June42 July34 Aug11 Sept23 Oct27 Discussion From the above data it can stated that is selected according the number of repetition of frequency (Marsden and Pingry, 2018).By analysis the information it can said that 11 is mode for this particular expenses as it has been repeated thrice in the shown tabular presentation. IV.Computation of range value Range is computed by analyzing the available data set and evaluating the highest and lowest number presented (Tan and et.al., 2021). On the basis of information available it can be range be determined by following below mentioned formula. Range = Higher expense- smaller value = 45- 5 = 40 On the basis of above determined value it can be interpreted that range for the selected type of expenditure is 40. V.Calculation regarding Standard Deviation Month s Money incurre d Mean (U) X- U (X- U)^2 Jan1122.1-11.1123.21 Feb1222.1-10.1102.01 Mar522.1-17.1292.41 April4522.122.9524.41
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May1122.1-11.1123.21 June4222.119.9396.01 July3422.111.9141.61 Aug1122.1-11.1123.21 Sept2322.10.90.81 Oct2722.14.924.01 Total 1850.9 SD= Square root of ∑(X-U)^2/N = Square root of 1850.9 / 10 = SQRT OF 185.09 = £ 13.60 Discussion of SD The determined value from applying the formula it can be stated that the standard deviation for transportation expense is 13.60. On the basis of this, it can be identified that there is moderated risk as moderate variation can be seen in it. 4.Forecasting model for linear equation is presented as below: Month s XYX*YX^2 Jan111111 Feb212244 Mar35159 April44518016
May5115525 June64225236 July73423849 Aug8118864 Sept92320781 Oct1027270100 Total552211340385 i.Determination of m value: m = Σxy – Σx Σy / Σ x^2 – (Σx)^2 = 1340-(55*221)/ 385- (55)^2 =(1340-12155) / (385-3025) = -10815/-2640 = 4.09 ii.Computation of value c is illustrated below C = Σy – m Σx / N = 221 – (4.09*55)/10 = -0.35 iii.Showing computation of 12thand 14thday Ascertainment of value in case of 12th Y= mX +c = 4.09(12) + (-0.35) = 49.08 - 0.35 =£48.73 Determination in case of 14th Y= mX +c = 4.09(14) + (-0.35)
= 57.26 +(-0.35) = 57.26 -0.35 = £56.91 Discussion From the above illustrated calculation it can be said thatvalue of m and c obtained are 4.09 and (-0.35). In order to get these values the given formula has been taken into consideration. On the basis of this values of 12thand 14thday are calculated by substituting m and c’s value which has given outcome48.73 and £56.91. CONCLUSION From the above report it can be summarized that numerical and data analysis plays significant role in current scenario to provide appropriate evaluation so that strategic decision can be taken. The present report has given emphasis on pictorial and tabular reflection of selected data set. In addition to this, practical exposure regarding mean, mode, median, range and SD can been seen in report. Case study has presented forecasting of linear equation to obtain m and c’s values to fulfill the objective of current report to ascertain the expenditure regarding mentioned period. 1.
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REFERENCES Books and Journals Marsden, J. R. and Pingry, D. E., 2018. Numerical data quality in IS research and the implications for replication.Decision Support Systems.115. pp.A1-A7. Tan, X. and et.al., 2021. The impact of uneven temperature distribution on stability of concrete structuresusingdataanalysisandnumericalapproach.Advancesin Structural Engineering.24(2). pp.279-290. Deuflhard, P. and Hohmann, A., 2021.Numerical analysis. de Gruyter. Gill, P. E., Murray, W. and Wright, M. H., 2021.Numerical linear algebra and optimization. Society for Industrial and Applied Mathematics.