This study focuses on numeracy and data analysis, covering topics such as arranging data, presenting data in charts, and calculating different elements. It also explores the use of linear forecasting models. The study concludes with a prediction of sleeping hours for day 11 and day 15.
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NUMERACY AND DATA ANALYSIS
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Contents MAIN BODY.................................................................................................................................................3 1. Arranging data in tabular format.........................................................................................................3 2. Presenting data in two different chart format.....................................................................................3 3. Calculation of different elements with the help of steps and highlighting of final value.....................4 CONCLUSION.............................................................................................................................................10
INTRODUCTION Analysis of numeracy and records always had to assess large data to help groups and their international operations. Individuals can forget the massive numbers with the aid of data collection and can provide some production which also assists in the corporation's decision- making method. This report mainly based on sleep per day on different days, as well as further research will be focused on the results. This analysis involves the different subjects and arranges data in table format, as well as the measurement of mode, mean, standard deviation and range. Additionally, companies or government departments willing to foresee the outcome with the aid of linear forecast model. MAIN BODY 1. Arranging data in tabular format There are mentioned data of sleep per day by a person on different days that are mentioned below in table format: DaySleeping hours 18 212 310 47 59 610 79 88 97 109 2. Presenting data in two different chart format Data presentation in column chart format and it mentioned below: Column chart: A column chart is a data presentation graph displaying vertical lines with the axis amountsfor the bars shown on the sample's left hand side. This is a visual item used inExcel spreadsheet to display the information. Ifwant to make comparisons throughout classes, thatcan use a line map.
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12345678910 0 2 4 6 8 10 12 8 12 10 7 9 10 9 8 7 9 Day Sleeping hours Scatter Plot: A scatter plot is a form of graph or numerical graph utilizing euclidean position and orientation to significant variable for a collection of data usually for 2 factors. If the dots are encrypted (coloured / texture / length), an external source can be seen. The information is provided as a series of points, all with the dependent variables assessing the horizontal plane stance and the valuation of all the other experience focused the velocity vector stance. 024681012 0 2 4 6 8 10 12 14 8 12 10 7 9 10 9 8 7 9 Sleeping hours Sleeping hours 3. Calculation of different elements with the help of steps and highlighting of final value Mean: For the mean of a sample population with a continuous random aspectsthe most popular phrase is the computational estimate of all words. To measure it, contribute the principles among all aspects and instead split them by terms amount. By incorporating the commodity of the
parameter with its likelihood as described by the allocation, the imply of a normal distribution with such a constant spontaneous factor, often termed the average value, is acquired. DaySleeping hours 18 212 310 47 59 610 79 88 97 109 Total89 Mean= Sum of all values/number of values = 89/10 = 8.9 Median: The median of an allocation with a continuous random distributiondepends about whether there is even and then strange valueof documents in the allocation. If the number of responses is strange and in the center the median is the average of the phrase. Itis the quality so that the percentage of aspects with principles roughly equivalent to that importance is worse than the amountof representatives with principles plus or minus equitable to that importance. If the valueof responses is even, therefore the median is the sumof 2terms in the centre, so the number of iterations intensity number approximately equal to a certain number is much like the amountof candidate’s intensity value to or less than equal to that. The following is determined by a formula: When data set is odd= (N+1)/2th item. When data set is even= {N/2thitem+ N/2thitem + 1}2
First of all, the data set needs to be arranged in ascending order: DaySleeping hours 17 27 37 48 58 69 79 89 910 1012 Total89 N= 10 M= (10/2th item + 10/2th item + 1)/2 = (5thitem+ 6thitem)/2 = (8+9)/2 = 8.5 Mode: A propagation model with a continuous random aspectis the meaning of the most commonly occurring expression. This is not unusual to have much more than one mode on a distributed with a differentprobability distribution, particularly when there aren't many words. This occurs if two or even more words occur equally frequently, and much more frequently than anyone else. DaySleeping hours 18 212 310 47
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59 610 79 88 97 109 Total89 The value of mode is 9 because frequency of this term is higher among all data. Thus mode is 9. Range: In numerical, discrepancy between some of the analysis higher or lower gain factor sequence distance Higher value= 12 Lower value= 7 Range= (12-7) = 5 Standard deviation: It is the calculation of diffusion quality from the collection of different data. Smaller standard deviation is similar to the average value, while high variance suggests a large variety of values. Calculating the normal distribution below this is as follows: DaySleeping hours x-m(x-m)2 19-0.10.01 2100.90.81 3122.98.41 48-1.11.21 57-2.14.41 69-0.10.01 78-1.11.21 87-2.14.41
99-0.10.01 10122.98.41 Total9128.9 Variance=[∑(x – mean)2/N] = (28.9/10) = 2.89 Standard deviation=√(variance) =√2.89 = 1.7 1.linear forecasting model which isy = mx + cin order to do below mentioned calculations: Calculation of value m: Y= mx+c m=n (∑xy) -(∑x)(∑y)/ n(∑x2)-(∑x)2 Day (x)Sleeping hours (y) x2Xy 1919 210420 312936 481632 572535 693654 784956
876456 998181 1012100120 5591385499 = 10(499) - (55)*(91)/10(385)-(55)2 = 4990-5005/3850-3025 = -15/825 = -0.018 Calculation of c: c=[(∑y) / n]-m (∑x/n) = [91/10] - (-0.018)(55/10) = 9.1-(-0.099) = 9.19 Forecasting for 11 and 15 days: Forecasting for day 11: y= mx+c = -0.018*11+9.19 = -0.20+9.19 = 8.99 or 9 hours Forecasting for day 15:
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= -0.018*15+9.19 = -0.27+9.19 = 8.92 hours CONCLUSION In the following study it is claimed that statistical analysis is too critical to identify any particular consequences of data gathering. Various values were calculated in this study, including such standard, mode, median and different others. The second part of the study ends with a conditional approximation of the sleeping hours predicted for day 11 and day 15.
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