Numeracy and Data Analysis: Tabular and Graphical Presentation of Data
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This report presents statistical data set in pictorial & tabular manner regarding advertisement expenditure. It includes calculation and discussion regarding the mead, mode, median, standard deviation. It involves utilization of linear forecasting model to fulfill the requirement of report by calculating m & c value.
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NUMERACYAND DATA ANALYSIS
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TABLE OF CONTENTS INTRODUCTION.......................................................................................................................................3 MAIN BODY..............................................................................................................................................3 1.Arranging the data related to advertisement expenses in the tabular format....................................3 2.Graphical representation of selected expenditure data.....................................................................4 3.Reflecting the required calculations as below:.................................................................................4 4.Forecasting linear equation model is shown as below:....................................................................9 CONCLUSION.........................................................................................................................................10 REFERENCES..........................................................................................................................................11
INTRODUCTION Numerical and Data Analysis (NDA) is the one of the important part to get accurate information for the purpose of decision making. In the current scenario, scope of data analysis has increased which improves efficiency and accuracy of strategic decision formulation practices of organization. The present report is based on presenting statistical data set in pictorial & tabular mannerregardingadvertisementexpenditure.Currentreportwillincludecalculationand discussion regarding the mead, mode, median, standard deviation. It will involve utilization of linear forecasting model to fulfill the requirement of report by calculating m & c value. MAIN BODY 1.Arranging the data related to advertisement expenses in the tabular format Serial No.MonthsMoneyincurredon Advertisement expenses 1Mar25 2April19 3May30 4June34 5July19 6Aug45 7Sept50 8Oct19 9Nov42 10Dec65
2.Graphical representation ofselected expenditure data Mar April May June July Aug Sept Oct Nov Dec 12345678910 0 10 20 30 40 50 60 70 Money spent on Advertisement expenses Money spent on Advertisement expenses Mar April May June July Aug Sept Oct Nov Dec 12345678910 0 10 20 30 40 50 60 70 Money spent on Advertisement expenses Money spent on Advertisement expenses 3.Reflectingthe required calculations asbelow: I.Mean Determination as follows: Serial No.MonthsMoneySpenton Advertisement expenses
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1Mar25 2April19 3May30 4June34 5July19 6Aug45 7Sept50 8Oct19 9Nov42 10Dec65 Totalamountofmoney incurredontransportation cost348 Total number of observation10 Mean34.8 Interpretation: From the above calculation it can be stated that mean derived is 34.8 which is obtained by dividing the total expense incurred for advertisement purpose by the number of observation (Cao, 2021). Mean for the advertisement expenditure in this particular situation is 34.8as per the above illustrated table. II.Median calculation shown below: In order to get the value of median there are two steps which need to emphasized which are as below that are implemented in sequence manner (Mölder and et.al., 2021). These both steps provides systematic procedure to get the value of median in accurate and reliable manner. Step 1: Arranging data in ascending order
Serial No.MonthsMoneyspenton Advertisement expenses 1April19 2July19 3Oct19 4Mar25 5May30 6June34 7Nov42 8Aug45 9Sept50 10Dec65 Step 2: Executing formula Median = (n+1)/2 Median (M)Number of observations10 M(10+1)/25.5 (30+34)/247 Interpretation: From the above table it can be analyzed that median is determined by giving conservation on 5Thand 6Thcell. The value of these cells are 30 and 34 respectively and by dividing it from 2 the value achieved is 47 which is median value of advertisement expenses (Babak and et.al., 2020). III.Mode computation as follows:
MonthsAdvertisement expenses Mar25 April19 May30 June34 July19 Aug45 Sept50 Oct19 Nov42 Dec65 Interpretation Mode can be assessed by evaluating the above illustrated table to get the value of expense that has been repeated more than one time (Fabián, 2021). From the analysis of data it can be interpreted that 19 has been observed thrice in table so it’s the mode for specified case. IV.Range calculation is reflected as follows Range is assessed by making analysis of the chosen data set to identify the highest and lowest range expenses (Munch, 2017). With help of applying formula as mentioned below range can be determined Range = Higher expense- smaller value = 65-19 = 46 Interpretation:
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The determined range value through substituting value of highest and lowest expenses which are 65 and 19 respectively & determined value by applying formula is 46. V.Standard Deviation is illustrated below Month s Money incurre d Mean (U) X- U (X- U)^2 Mar2534.8-9.896.04 April1934.8-15.8249.64 May3034.8-4.823.04 June3434.8-0.80.64 July1934.8-15.8249.64 Aug4534.810.2104.04 Sept5034.815.2231.04 Oct1934.8-15.8249.64 Nov4234.87.251.84 Dec6534.830.2912.04 Total 2167.6 SD= Square root of ∑(X-U) ^2/N = Square root of2167.6/ 10 = SQRT OF 216.76 = 14.72 Interpretation: The standard deviation for advertisement expense is 14.72 which have been computed by implementing mentioned formula.
4.Forecasting linear equation model is shown as below: MonthsXYX*YX^2 Mar125251 April219384 May330909 June43413616 July5199525 Aug64527036 Sept75035049 Oct81915264 Nov94237881 Dec1065650100 Total 553482184385 i.Determination of m value: m = Σxy – Σx Σy / Σ x^2 – (Σx)^2 =2184-(55*348)/385- (55)^2 = (2184- 19140) / (385-3025) = -16956/ -2640 = 6.42 ii.Computation of value c is illustrated below C = Σy – m Σx / N = 348 – 6.42 (55)/10 = 348- 353.1/ 10 = -0.51 iii.Showing calculations of 12thand 14thMonth
Determination of 12thmonth Y= mX +c = 6.42(12) + (-0.51) = 77.04- 0.51 = 76.53 Calculation of 14thmonth expense Y= mX +c = 6.42 (14) + (-0.51) = 89.88 – 0.51 = 89.37 Interpretation: With help of above shown computation it can be interpreted that m and c value has been derived by following systematic formula given (Lester, Cho and Lochmiller, 2020). Values of m and c are 6.42 &(-0.51) respectively. Specific expenditure for the month of 12thand 14thare 76.53 & 89.37 respectively. CONCLUSION From the above report it can be concluded that numeracy and data analysis are crucial for the purpose formulating important decisions in respect to the growth of firm. The present report has included the tabular and graphical presentation of data. It has include calculation ofmean, mode, median, range, standard deviation, etc. in addition to this , current case study has forecast the linear equationfor the purpose of calculating m and c values.Both the values has been calculated by applying given formula to meet the requirement of present report.
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REFERENCES Books and Journals Babak, V. and et.al.,2020. Methods and models for information data analysis.Diagnostic Systems for Energy Equipments. Studies in Systems, Decision and Control. 281. pp.23-70. Cao, W., 2021. Discussion on Mean, Median, Mode and its Validity and Table Number.Journal of Contemporary Educational Research.5(3). Fabián, Z., 2021. Mean, mode or median? The score mean.Communications in Statistics-Theory and Methods.50(10). pp.2360-2370. Lester, J. N., Cho, Y. and Lochmiller, C. R., 2020. Learning to do qualitative data analysis: A starting point.Human Resource Development Review.19(1). pp.94-106. Mölder, F. and et.al., 2021. Sustainable data analysis with Snakemake.F1000Research.10. Munch, E., 2017. A user’s guide to topological data analysis.Journal of Learning Analytics. 4(2), pp.47-61.