NURSING STATISTICS2
In the above case control study to find the association between alcohol consumption and liver
cancer, it has been found that the odd ratio is approximately 3.6. The OR value is much
higher than the probability testing value 1 and therefore it indicates that people who drinks
more than 12 ounces alcohol per day has much higher chances of suffering from liver cancer
than the people who drink less.
Confidence Interval Calculation
logOR 0.555879
SE(logOR) sqrt((1/410)+(1/450)+(1/190)+(1/750)
)
0.106 z-value for
95% CI is 1.96
UL: 95%
Confidence
Interval for OR
EXP(logOR+(z*SE(logOR))) EXP(0.556+(1.96*0.106)) 2.146
LL: 95%
Confidence
Interval for OR
EXP(logOR-(z*SE(logOR)) EXP(0.556-(1.96*0.106)) 1.416
From the above result of confidence interval it has been found that considering the 95%
confidence interval in the chosen population the CI range of OR is 1.416 to 2.146. Therefore,
it can be seen that both lower level of 95% CI and Upper level of 95% CI are higher than 1.
Therefore, for the chosen population the association or odd ratio result is statistically
significant. In other words, of 95% of the chosen population the OR ranged from 1.4 to 2.1.
b)
Average
alcohol
consumption
per day
Never Smokers
Cases Controls Total
≥ 12 ounces 90 200 290
< 12 ounces 110 220 330
Total 200 420 620
OR (410*750)/(450*190) 0.900

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The Assignment on Nursing Statistics

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