Using Numeracy, Data and IT for Analysis of Olympic Medals

USING NUMERACY,
DATA AND IT

TABLE OF CONTENTS
PART-2......................................................................................................................................3
Question 11.............................................................................................................................3
Question 12.............................................................................................................................5
Question 13.............................................................................................................................5
Question 14.............................................................................................................................7
Question 15...........................................................................................................................10
Part- 3.......................................................................................................................................12
Question 16...........................................................................................................................12
References................................................................................................................................15
Books and journal.................................................................................................................15
Online reference...................................................................................................................15

PART – 1
Question 1
Numerator and denominator can be explained as a part of fraction which consists of
two values where one of these values has been placed on the top which is known as
numerator and the other value has been placed at the bottom and is known as denominator.
The numerator and denominator are separated by a line which is also known as a fractional
bar. For example, given a fraction number is ¾, where 3 is the numerator and 4 is the
denominator and a slanting line separating these values is what the fractional bar. Also, the
numerator indicates the selected number of parts out of the available total equal number of
parts.
Question 2
Simplification process of fraction begins with the identification of HCF or Highest Common
Factor from the integer values involving numerator and denominator. The division of both
numerator and denominator will be done with the Highest Common Factor in the next step.
At last the reduced factor has been determined which is also known as simplified value of a
given fraction.
By taking the example of the given fraction, simplification process can be explained easily,
which is as follows:
HCF of 24 / 40 is 8, where after dividing both numerator and denominator with HCF, we will
get the simplified form of the fraction that is, 3 / 5.
Similarly, the second fraction given here is 18 / 42 whose HCF is 6 and by dividing both the
numerator and denominator with its HCF, we will get the simplified form of the fraction that
is, 3 / 7.
Therefore, with the help of determined value of HCF, one can easily simplified the fraction to
its simplified form.
Question 3
a) Equivalent fraction can be defined as all those fractions involving different numbers but
are indicating the same part selected out of the whole through numerator and denominator. In
other words, fraction with different values of numerator and denominator having equal
fractional value in its simplified form. For example, ½ can also be written as 5/10 and 50/100
indicating a same fractional value equivalent to half when it gets simplified.
In the given case, fractions 2/3, ¾ and 5/6 can be expresses as equivalent fractions having its
denominator equals to 12 as follows:
The equivalent fractions can be formed for the given fractions by multiplying their numerator
and denominator with the same values.
 If the fraction 2/3 gets multiplied by 4/4, the resulting fraction would be 8 / 12.
 If the fraction 3 / 4 gets multiplied by 3/3, the resulting fraction would be 9 / 12.
 If the fraction 5 /6 gets multiplied by 2 / 2, the resulting fraction would be 10 / 12.
Therefore, all these fractions have similar number in its denominator that is 12, and all these
fractions can be termed as equivalent fraction as they are indicating the similar values.

b) In order to determine the percentage of computing books within the library, in the first step
the remaining number of books needed to be determined as follows:
Remaining books after subtracting books on other subject from the total number of books
= 60000 – 14000 – 22000 – 12000 = 12000 books.
It is given that computing books form 2 / 3 part of the remaining books that is, 2/3 * 12000 =
8000. So, there are 8000 books in the library on the subject computing.
To determine the percentage value of computing books, the number of computing books will
be divided by the total number of books in the library and the resulting value again gets
multiplied by 100 as follows:
8000 / 60000 * 100 = 13.33% of the total books in the library are on computing.
Question 4
Total number of shoe pairs bought = 2
Amount received by sales attendant from Liz = 3 * 50 = £150
Amount returned by sales attendant to Liz = £10.5
Therefore, the derived value of each pair of shoes charged by the sales attendant
= £150 - £10.5 / 2 = £139 .5 / 2 = £69.75.
Cost of each pair = £69.75.
Question 5
a) Computation of 240.5 * 19.54 = 4699.37 which is showing relevant results as it is having
two significant values.
b) In the form of power of 10, the number 52100 can be written as 5.21 * 104.
Question 6
a) Amount paid for 3 people = £210 (discounted charge @ 30%)
£210 = 70%
So, the 100% amount would be = 210/70 * 100 = £300
In the absence of discount, the amount paid would be = £300
Total discount availed = £300 - £210 = £90.
b) Total discount availed is equals to total savings made that is, £90 for 3 persons.
Average savings per person = £90/3 = £30 per person.
Question 7
a) 3 / 4 – 7/9 + 2/3 = 0.75 – 0.78 + 0.67 = 0.64 = 16 / 25.
b) 0.1 is the largest of all the given numbers.
Question 8
Total people question = 150 (90 men and 60 women)