Programming Project: Solving System of Linear Equations and Implementing MATLAB Script

In this document we will discuss about Programming Project and below are the summary points of this document:- The programming project involves solving a system of linear equations using matrix multiplication. The project consists of two parts, with the first part discussing the given equations and their expansion. The second part involves implementing a MATLAB script to solve for unknown temperatures in the system.

Running head: PROGRAMMING PROJECT
PROGRAMMING PROJECT
Name of the Student
Name of the University
Author Note

1PROGRAMMING PROJECT
Part 1:
1. i)
Given system of linear equations are
T 1
2=T 0, for m = 1
−τ T m−1
2 + ( 1+ 2 τ ) T m
2 −τ Tm +1
2 =T m
1 + τ∗ ˙g ( Δx ) 2
k , for m = 2,3,4
T 5
2=T L for m=5
Expanding equations for m=2, 3, 4 gives
T 1
2=T 0
−τ T 1
2+ ( 1+ 2 τ ) T 2
2−τ T 3
2=T 2
1+ τ∗ ˙g ( Δx )2
k
−τ T 2
2+ ( 1+ 2 τ ) T 3
2−τ T 4
2 =T3
1 + τ∗˙g ( Δx ) 2
k
−τ T 3
2+ ( 1+ 2 τ ) T 4
2 −τ T5
2=T 4
1 + τ∗ ˙g ( Δx )2
k
T 5
2=T L
Now, in standard matrix multiplication format, A T 2=b, where A = 5*5 matrix and b is 5*1
matrix is given below.
[ 1 0 0 0 0
−τ ( 1+ 2 τ ) −τ 0 0
0 −τ ( 1+2 τ ) −τ 0
0 0 −τ ( 1+2 τ ) −τ
0 0 0 0 1 ] [ T1
2
T2
2
T3
2
T 4
2
T5
2 ] =
[ T 0
T 2
1 + τ∗ ˙g ( Δx ) 2
k
T 3
1 + τ∗ ˙g ( Δx ) 2
k
T 4
1 + τ∗˙g ( Δx ) 2
k
T L
] (1)

2PROGRAMMING PROJECT
ii) Now, the values of τ = 1/3, T 0 = T L = 1, ˙g ( Δx ) 2
k = 1 and T 1 =
[ 1
1
1
1
1 ] are put into matrix
equation (1). Hence, T 1
1=T 2
1 =T3
1 =T 4
1 =T 5
1=1
[ 1 0 0 0 0
−1
3 ( 5
3 ) −1
3 0 0
0 −1
3 (5
3 ) −1
3 0
0 0 −1
3 ( 5
3 ) −1
3
0 0 0 0 1
] [T1
2
T2
2
T3
2
T 4
2
T5
2 ]=
[ 1
4
3
4
3
4
3
1
]
Part 2:
Now, a MATLAB script LO8.m is written to solve the unknown T 2 when T 1 are given. The
necessary parameters remains the same as given in part 1.
MATLAB code:
%% Defining paramters
tau = 1/3; T0 = 1; TL = 1; gdotdelxsqrbyk = 1;
%% defining initial nodal temepratures
Tsup1 = [1 1 1 1 1]';
A = [1 0 0 0 0;-tau (1+2*tau) -tau 0 0;0 -tau (1+2*tau) -tau 0;0 0 -tau (1+2*tau) -tau;0 0 0 0
1];

3PROGRAMMING PROJECT
b = [T0 Tsup1(2)+tau*gdotdelxsqrbyk Tsup1(3)+tau*gdotdelxsqrbyk
Tsup1(4)+tau*gdotdelxsqrbyk TL]';
fprintf('The coefficient matrix is \n')
A
fprintf('The constant matrix is \n')
b
%% Solving for unknown nodal temperatures
Tsup2 = A\b;
fprintf('The unknown temperatures in matrix form is \n')
Tsup2
Output:
The coefficient matrix is
A =
1.0000 0 0 0 0
-0.3333 1.6667 -0.3333 0 0
0 -0.3333 1.6667 -0.3333 0
0 0 -0.3333 1.6667 -0.3333
0 0 0 0 1.0000

4PROGRAMMING PROJECT
The constant matrix is
b =
1.0000
1.3333
1.3333
1.3333
1.0000
The unknown temperatures in matrix form is
Tsup2 =
1.0000
1.2609
1.3043
1.2609
1.0000

5PROGRAMMING PROJECT
Hence, the unknown temperature matrix is
[ T 1
2
T 2
2
T 3
2
T 4
2
T 5
2 ]=
[ 1
1.2609
1.3043
1.2609
1 ]