Physics Practice Problems and Solutions

Suggested Solutions
1. (a) (i)
(ii) to estimate the distance between Oxford and Didcot, we need to find the area under the
graph since displacement can be obtained from integrating the velocity function.
S= ( 1
2 ×200 × 36 )+ ( 1
2 × ( 36 +40 ) × 40 ) + ( 40 ×120 ) + ( 1
2 × ( 40+38 ) × 40 )+ ( 1
2 × 200× 38 )
S ≈ 15280 m

(b)
2. (a) (i)
U x=45 cos 50=28.93 m/s
U y=45 sin 50=34.47 m/s
(ii) The x and y components of the balls acceleration
10m