Pipetting Chemistry Practical Report 2022
Added on 2022-12-12
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Running head: CHEMISTRY 0
CHEMISTRY
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CHEMISTRY
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CHEMISTRY 1
Practical report on pipetting, its precision and accuracy
Aim
To understand how to select the most accurate equipment that can be used to perform
measurements of volume
To carry out the precision and accuracy of the recorded measurements
Method
The practical exercise was carried in strict accordance to the procedure guide that was provided
for conducting the exercise. For the method used, refer to the procedure in (Introduction to
pipetting, 2019)
Observations
Pipetting was carried out for different volumes of water into the weighing equipment in
order to find out the water volume that is actually transferred. The water density is often
known a 0.998g/ml at normal room temperature. This implies that a milliliter of water has
got an equivalent mass of 1 gram, thus 0.05 milliliter of water equally has a mass of
50mg ("How to pipette correctly – a short step-by-step introduction into proper
pipetting", 2019).
The same volume is pipetted several times in order to enable the determination of the
mean volume in order to compare it with each reading whether they are similar. Re-using
a tip a number of times equally influence the measurement obtained.
There is an observation of some liquid that tends to remain in the tube. To measure the
liquid, first draw it up and then adjust the volume of the pipette such that the air below
the liquid is removed from the tip. The pipette should always be maintained in a vertical
position while performing this procedure.
A fresh tip is used each time in order to avoid cross contamination
Practical report on pipetting, its precision and accuracy
Aim
To understand how to select the most accurate equipment that can be used to perform
measurements of volume
To carry out the precision and accuracy of the recorded measurements
Method
The practical exercise was carried in strict accordance to the procedure guide that was provided
for conducting the exercise. For the method used, refer to the procedure in (Introduction to
pipetting, 2019)
Observations
Pipetting was carried out for different volumes of water into the weighing equipment in
order to find out the water volume that is actually transferred. The water density is often
known a 0.998g/ml at normal room temperature. This implies that a milliliter of water has
got an equivalent mass of 1 gram, thus 0.05 milliliter of water equally has a mass of
50mg ("How to pipette correctly – a short step-by-step introduction into proper
pipetting", 2019).
The same volume is pipetted several times in order to enable the determination of the
mean volume in order to compare it with each reading whether they are similar. Re-using
a tip a number of times equally influence the measurement obtained.
There is an observation of some liquid that tends to remain in the tube. To measure the
liquid, first draw it up and then adjust the volume of the pipette such that the air below
the liquid is removed from the tip. The pipette should always be maintained in a vertical
position while performing this procedure.
A fresh tip is used each time in order to avoid cross contamination
CHEMISTRY 2
In case the pipette is contaminated on its outside, it is first wiped with an ethanol on its
outside ("17 Ways to Stop Pipetting Errors From Ruining Your Experiments - Bitesize
Bio", 2019).
Results
Containers' weights for the 20mL solution are recorded below
Containers' weights for the 10mL solution are recorded below
Calculations
20mL solution
Use the equation, with water – without water to find the mass of water (m).
(C1) 319002 g + 120472 g = (m1) 19.8530 g
(C2) 321476 g + 121829 g = (m2) 19.9647 g
(C3) 317217 g + 118878 g = (m3) 19.8339 g
20 mL solution Without Water With Water
Container 1 (C1) 120472 g 319002 g
Container 2 (C2) 121829 g 321476 g
Container 3 (C3) 118878 g 317217 g
10 mL solution Without Water With Water
Container 1 (C1) 120472 g 219724 g
Container 2 (C2) 121829 g 221589 g
Container 3 (C3) 118878 g 218356 g
In case the pipette is contaminated on its outside, it is first wiped with an ethanol on its
outside ("17 Ways to Stop Pipetting Errors From Ruining Your Experiments - Bitesize
Bio", 2019).
Results
Containers' weights for the 20mL solution are recorded below
Containers' weights for the 10mL solution are recorded below
Calculations
20mL solution
Use the equation, with water – without water to find the mass of water (m).
(C1) 319002 g + 120472 g = (m1) 19.8530 g
(C2) 321476 g + 121829 g = (m2) 19.9647 g
(C3) 317217 g + 118878 g = (m3) 19.8339 g
20 mL solution Without Water With Water
Container 1 (C1) 120472 g 319002 g
Container 2 (C2) 121829 g 321476 g
Container 3 (C3) 118878 g 317217 g
10 mL solution Without Water With Water
Container 1 (C1) 120472 g 219724 g
Container 2 (C2) 121829 g 221589 g
Container 3 (C3) 118878 g 218356 g
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